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taurus [48]
1 year ago
11

Sharon is 54 inches tall. tree in her backyard is five times as tall as she is. the floor of her treehouse is at a height that i

s twice as tall as she is. What is the difference in inches between the top of the tree and the floor of the treehouse?
Mathematics
2 answers:
mafiozo [28]1 year ago
3 0
First to solve this problem you are going to figure out how tall the tree is. So if Sharon is 54 inches and the tree 5 times the height she is you would do 54*5= 270. Next you go to find out how tall the floor of her tree house is. It says the floor is twice the height of her so you would do 54*2=108. Then the problem asks the difference between the top of the tree and the floor of the tree house. So 270-108=162. I hope this helped. :) Brainliest answer?
Guest1 year ago
0 0

270 (54x5)

Guest
1 year ago
I will be ur bf
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7 0
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4C. Quintin is using the three different shaped
Sauron [17]

The smallest number of tiles Quintin will need in order to tile  his floor is 20

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To find:

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Among the three different shapes available, total area of one is calculated as;

A_{one \ square \ type} = 5 \times 2000 \ cm^2 = 10,000 \ cm^2

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The maximum number tiles needed (this will be possible if only one shape type is used)

maximum \ number= \frac{Area \ of \ floor}{total \ area \ of \ one \ shape \ type} \\\\maximum \ number= \frac{600,000 \ cm^2}{10,000 \ cm^2} \\\\maximum \ number=  60

When all the three different shape types are used we can get the smallest number of tiles needed.

The minimum or smallest number of tiles needed (this will be possible if all the 3 different shapes are used)

3 \times \ smallest \ number  = 60\\\\smallest \ number = \frac{60}{3} \\\\smallest \ number = 20

Thus, the smallest number of tiles Quintin will need in order to tile  his floor is 20

Learn more here: brainly.com/question/13877427

3 0
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