Question

Find the approximate side lengths and perimeter of quadrilateral WXYZ. If necessary, round your answers to the nearest hundredth.
The approximate length of segment WX is
$\left[\begin{array}{ccc}2\\4.12\\4.47\\5\end{array}\right]$

The approximate length of segment XY is
$\left[\begin{array}{ccc}2\\4.12\\4.47\\5\end{array}\right]$

The approximate length of segment YZ is
$\left[\begin{array}{ccc}2\\4.12\\4.47\\5\end{array}\right]$

The approximate perimeter of quadrilateral WXYZ is $\left[\begin{array}{ccc}14\\14.47\\15\\15.59\end{array}\right]$

Answer 1

Answer:

The answer is given below

Step-by-step explanation:

Given that the location of the points are W = (3, 1) , X = (7, -1), Y = (7, -3) and Z = (3,-3)

The distance between two points A(x1, y1) and B(x2, y2) is given by the formula:

$|AB|=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

Therefore, the side length of the quadrilaterals are:

$|WX|=\sqrt{(-1-1)^2+(7-3)^2}=\sqrt{20} =4.47$

$|XY|=\sqrt{(-3-(-1))^2+(7-7)^2}=\sqrt{20} =2\\\\|YZ|=\sqrt{(-3-(-3))^2+(3-7)^2}=\sqrt{20} =4\\\\|ZW|=\sqrt{(-3-1)^2+(3-3)^2}=\sqrt{20} =4$

The Perimeter of the quadrilateral = |WX| + |XY| + |YZ| + |ZX| = 4.47 + 2 + 4 + 4 = 14.47 units