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ivanzaharov [21]
2 years ago
10

Which of the following are possible equations of a parabola that has no real solutions and opens downward?

Mathematics
2 answers:
bekas [8.4K]2 years ago
6 0

Answer:

y =  -  {(x - 4)}^{2}  - 2

y =  -  {(x + 4)}^{2}  - 2

Step-by-step explanation:

The vertex form of a parabola is given as

y = a {(x - h)}^{2}  + k

If this parabola opens downward, then a<0.

This means for a function opening downward not to have a solution, the k value must also be negative and taking a square root of a negative number will not give real solution.

From the given options, examples of such functions are:

y =  -  {(x + 4)}^{2}  - 2

and

y =  -  {(x  - 4)}^{2}  - 2

icang [17]2 years ago
5 0

Answer:it’s y>=-(x+4)^2-2

Step-by-step explanation:

I checked it in my graphing calculator and it works. I’m also doing the program sooo

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Answer:

$1000.00

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The supervisor is asking for an expense form of a <u>total (?) </u>when you return.

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2 years ago
400 students were randomly sampled from a large university, and 289 said they did not get enough sleep. Conduct a hypothesis tes
melomori [17]

Answer:

The sample proportion represents a statistically significant difference from 50%

Step-by-step explanation:

Null hypothesis: The sample proportion is the same as 50%

Alternate hypothesis: The sample proportion is not the same as 50%

z = (p' - p) ÷ sqrt[p(1 - p) ÷ n]

p' is sample proportion = 289/400 = 0.7225

p is population proportion = 50% = 0.5

n is number of students sampled = 400

z = (0.7225 - 0.5) ÷ sqrt[0.5(1 - 0.5) ÷ 400] = 0.2225 ÷ 0.025 = 8.9

The test is a two-tailed test. Using a 0.01 significance level, critical value is 2.576. The region of no rejection of the null hypothesis is -2.576 and 2.576.

Conclusion:

Reject the null hypothesis because the test statistic 8.9 falls outside the region bounded by the critical values -2.576 and 2.576.

There is sufficient evidence to conclude that the sample proportion represents a statistically significant difference from 50%.

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2 years ago
A fisherman catches fish according to a Poisson process with rate lambda = 0.6 per hour. The fisherman will keep fishing for two
spayn [35]

Answer:

Step-by-step explanation:

Given that a fisherman catches fish according to a Poisson process with rate lambda = 0.6 per hour.

The fisherman will keep fishing for two hours.

Since he continues till he gets atleast one fish, we can calculate probability as follows:

(a) Find the probability that he stays for more than two hours.

= Prob (x=0) in I two hours and P(X≥1) in 3rd hour

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= 0.5488^2*(1-0.8781)\\\\=0.2645

(b) Find the probability that the total time he spends fishing is between two and five hours.

Prob that he does not get fish in I two hours * prob he gets fish between 3 and 5 hours

=P(0)^2 *F(1)^3\\=0.5488^2*0.2645^3\\=0.00557

(c) Find the expected number offish that he catches.

Expected value in Geometric distribution = \frac{1-p}{p}, where p = prob of getting 1 fish in one hour

= \frac{0.6}{1-0.6} \\=3

(d) Find the expected total fishing time, given that he has been fishing for four hours.

= Expected fishing time total/expected fishing time for 4 hours

=3/0.6*4

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