The most likely answer is D) <span>"The date that the check is written is usually a few days before it is cashed. We record when it was cashed and you record when its written".

There is usually a delay between when you write someone a check (and record it in your ledger) and when that person cashes it (when the bank records it). </span>

7 0

1 year ago

Every day, Jorge buys a lottery ticket. Each ticket has a probability of of winning a prize. After six days, what is the probabi

Romashka [77]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Every day, Jorge buys a lottery ticket. Each ticket has a 0.16 probability of winning a prize. After six days, what is the probability that Jorge has won at least one prize? Round your answer to four decimal places.

Answer:

The probability that Jorge has won at least one prize after six days is

P(at least 1 win) = 0.6487

Step-by-step explanation:

Every day, Jorge buys a lottery ticket which has a 0.16 chance of winning a prize.

We want to find out the probability that Jorge has won at least one prize after six days.

P(at least 1 win) = 1 - P(not winning for 6 days)

We know that the probability of winning is 0.16 then the probability of not winning is

P(not winning) = 1 - 0.16 = 0.84

For 6 days,

P(not winning for 6 days) = 0.84×0.84×0.84×0.84×0.84×0.84

P(not winning for 6 days) = 0.84⁶

P(not winning for 6 days) = 0.3513

Finally,

P(at least 1 win) = 1 - P(not winning for 6 days)

P(at least 1 win) = 1 - 0.3513

P(at least 1 win) = 0.6487

6 0

2 years ago

A recent survey showed that among 100 randomly selected college seniors, 20 plan to attend graduate school and 80 do not. determ

Temka [501]

The confidence interval would be (0.122, 0.278).

We first find our z-score. We want a 95% confidence interval:

0.95/2 = 0.475

Looking this up in the z-table, (http://www.statisticshowto.com/tables/z-table/) we see the z-score is 1.96.

The formula we will use is:

$p \pm z\sqrt{\frac{p(1-p)}{n}}$

In this problem, p = 20/100 = 0.2, and n=100:

$0.2 \pm 1.96\sqrt{\frac{(0.2)(0.8)}{100}}
\\
\\0.2\pm 0.0784
\\
\\(0.2-0.0784, 0.2+0.0784)
\\
\\(0.1216,0.2784)$

8 0

2 years ago