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2 years ago

What is the relationship between two lines whose slopes are −8 and 1 8 ?

Mathematics

2 answers:

zavuch27 [327]2 years ago

5 0

Answer:

They are perpendicular lines

Step-by-step explanation:

If one line has slope -8 and the other one has slope 1/8, they must be perpendicular to each other because the condition for perpendicular lines is that the slope of one must be the "opposite of the reciprocal of the slope of the original line."

the opposite of -8 is 8 , and the reciprocal of this is 1/8

JulijaS [17]2 years ago

3 0

Answer:

Below

Step-by-step explanation:

Let m and m' be the slopes of two different lines.

These lines are peependicular if and only if:

● m×m' = -1

Notice that:

● -8 ×(1/8) = -1

So the lines with the respectives slopes -8 and 1/8 are perpendicular.

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In parallelogram ABCD , diagonals AC⎯⎯⎯⎯⎯ and BD⎯⎯⎯⎯⎯ intersect at point E, AE=x2−16 , and CE=6x .

MAXImum [283]

Answer:

<h3>AC=96 units.</h3>

Step-by-step explanation:

We are given a parallelogram ABCD with diagonals AC and BD intersect at point E.

$AE=x^2-16.$ , and CE=6x .

Note: The diagonals of a parallelogram intersects at mid-point.

Therefore, AE = EC.

Plugging expressions for AE and EC, we get

$x^2-16=6x.$

Subtracting 6x from both sides, we get

$x^2-16-6x=6x-6x$

$x^2-6x-16=0$

Factoriong quadratic by product sum rule.

We need to find the factors of -16 that add upto -6.

-16 has factors -8 and +2 that add upto -6.

Therefore, factor of $x^2-6x-16=0$ quadratic is (x-8)(x+2)=0

Setting each factor equal to 0 and solve for x.

x-8=0 => x=8

x+2=0 => x=-2.

We can't take x=-2 as it's a negative number.

Therefore, plugging x=8 in EC =6x, we get

EC = 6(8) = 48.

<h3>AC = AE + EC = 48+48 =96 units.</h3>

5 0

2 years ago

Suppose X is the breaking strength (newtons) of a material, and X is normally distributed with

Veronika [31]

Answer:

a) 0.997 is the probability that the breaking strength is at least 772 newtons.

b) 0.974 is the probability that this material has a breaking strength of at least 772 but not more than 820

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 800 newtons

Standard Deviation, σ = 10 newtons

We are given that the distribution of breaking strength is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P( breaking strength of at least 772 newtons)

$P(x \geq 772)$

$P( x \geq 772) = P( z \geq \displaystyle\frac{772 - 800}{10}) = P(z \geq -2.8)$

$= 1 - P(z$

Calculation the value from standard normal z table, we have,

$P(x \geq 772) = 1 - 0.003 = 0.997 = 99.7\%$

0.997 is the probability that the breaking strength is at least 772 newtons.

b) P( breaking strength of at least 772 but not more than 820)

$P(772 \leq x \leq 820) = P(\displaystyle\frac{772 - 800}{10} \leq z \leq \displaystyle\frac{820-800}{10}) = P(-2.8 \leq z \leq 2)\\\\= P(z \leq 2) - P(z < -2.8)\\= 0.977 - 0.003 = 0.974 = 97.4\%$