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eimsori [14]
2 years ago
7

Which statements can be represented by this equation? Select three options.

Mathematics
2 answers:
mars1129 [50]2 years ago
5 0

Answer:

Options A,C and E.

Step-by-step explanation:

The given equation is

2n-9.2=n+\dfrac{4}{5}

Let n be the unknown number, then

Twice a number minus nine and two-tenths is the same as the number plus four-fifths.

2n-9.2=n+\dfrac{4}{5}

So, option A is correct.

Nine point two decreased by double a number is the same as the number added to four-fifths.

9.2-2n=n+\dfrac{4}{5}

Nine point two less than twice a number is equal to the number added to four-fifths.

2n-9.2=n+\dfrac{4}{5}

So, option C is correct.

Two times the difference of a number and nine and two-tenths is equal to the number plus four-fifths.

2(n-9.2)=n+\dfrac{4}{5}

Double a number decreased by nine and two-tenths is the same as the sum of four-fifths and the number.

2n-9.2=n+\dfrac{4}{5}

So, option E is correct.

Therefore, the correct options are A,C and E.

Volgvan2 years ago
5 0

Answer:

<h3>A, C, and E</h3><h3>Step-by-step explanation: i did the quiz on Edg</h3>
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Which shows one way to determine the factors of 12x3 – 2x2 + 18x – 3 by grouping?
Debora [2.8K]

Option A

2x^2(6x-1) + 3(6x-1) is one way to determine the factors of 12x^3-2x^2+18x-3 by grouping

<em><u>Solution:</u></em>

Factoring by grouping means that you will group terms with common factors before factoring

<em><u>Given expression is:</u></em>

12x^3-2x^2+18x-3

Group the first two terms together and then the last two terms together.

(12x^3-2x^2)+(18x-3)

We can see that 2x^2 is common in first two terms

And 3 is common in last two terms

Factor them out

(12x^3-2x^2)+(18x-3) = 2x^2(6x-1) + 3(6x-1)

2x^2(6x-1) + 3(6x-1)

Thus option A is correct

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1 year ago
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A race car driver lost 8 seconds off the leader for each of the 3 pit stops the driver made. At each of the next 2 pit stops the
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2 years ago
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The difference between number 20 and its opposite is what percentage of 200? (if you do not remember: opposite of 15 is −15; opp
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The heights of the trees for sale at two nurseries are shown below. Heights of trees at Yard Works in feet : 7, 9, 7, 12, 5 Heig
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Answer:

The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

Step-by-step explanation:

1). Height of the trees at Yard Works are = 7,9,7,12,5 feet

So mean height of the trees = (7+9+7+12+5)÷5

                                               = 40÷5 =8 feet

Standard deviation of the trees at Yard works = ∑(║(height of the tree-mean height of the tree))║/(number of trees)

(height of the tree-mean height of the tree)= ║(7-8)║+║(9-8)║+║(7-8)║+║(12-8)║+║(5-8)║ = (1)+1+(1)+4+(3)= 10

Therefore standard deviation = (10)/(5) =2

2). In the same way mean height of the trees at Grow Station=(9+11+6+12+7)/5= 45/5 = 9

Now we will calculate the mean deviation of the tress at Grow Station

= ∑║(height of the tree-mean height of the tree)║/(number of trees)

= ║(9-9)║+║(11-9)║+║(6-9)║+║(12-9)║+║(7-9)║/(5)

= (0+2+3+3+2)/5

= 10/5 =2

Therefore The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

                                                             

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