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Luden [163]
2 years ago
9

In complete sentences, explain whether or not it makes sense to say that the density of helium is 0.1785 kilograms per square me

ter.
Mathematics
2 answers:
Elenna [48]2 years ago
8 0

Answer:

No

Step-by-step explanation:

No, it does not make any sense to say that the density of helium is  0.1785 kilograms per square meter because because density of helium, and all the rest of the chemicals, are calculated by unit mass per unit volume as the density is given as:

Density=\frac{Mass}{Volume}

where mass is measured in kilograms and volume is measured in cubic meter.

Thus, the density of the helium will be 0.1785kgm^{-3} that is 0.1785 kilograms per cubic meter.

lubasha [3.4K]2 years ago
5 0
No it does NOT make sense to state density in kilograms per square meter.  Density has to be stated in terms of mass per unit of volume and NOT per unit of area. 
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Determine the product: (46.2 × 10–1) ⋅ (5.7 × 10–6). Write your answer in scientific notation.
lianna [129]

Answer:

A

Step-by-step explanation:

10-6 X 10-1 = 10-7

5.7*46.2=263.34

263.34=2.6334 x 10^2

10^2 x 10^-7 = 10^-5

so

=2.6334 x 10-5

7 0
2 years ago
Fiona wrote the linear equation y = x – 5. When Henry wrote his equation, they discovered that his equation had all the same sol
Oliga [24]
His equation could be written in quadratic form, which is ax^2+bx=c                     


7 0
2 years ago
Read 2 more answers
For the binomial expansion of (x + y)^10, the value of k in the term 210x 6y k is a) 6 b) 4 c) 5 d) 7
Sloan [31]

Answer:

a) 6

Step-by-step explanation:

Expanding the polynomial using the formula:

$(x+y)^n=\sum_{k=0}^n \binom{n}{k} x^{n-k} y^k $

Also

$\binom{n}{k}=\frac{n!}{(n-k)!k!}$

I think you mean 210x^6y^4

We can deduce that this term will be located somewhere in the middle. So I will calculate k= 5; k=6 \text{ and } k =7.

For k=5

$\binom{10}{5} (y)^{10-5} (x)^{5}=\frac{10!}{(10-5)! 5!}(y)^{5} (x)^{5}= \frac{10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5! }{5! \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 } \\ =\frac{30240}{120} =252 x^{5} y^{5}$

Note that we actually don't need to do all this process. There's no necessity to calculate the binomial, just x^{n-k} y^k

For k=6

$\binom{10}{6} \left(y\right)^{10-6} \left(x\right)^{6}=\frac{10!}{(10-6)! 6!}\left(y\right)^{4} \left(x\right)^{6}=210 x^{6} y^{4}$

5 0
2 years ago
Joe drove 100 miles from San Francisco to Gilroy and used 4 gallons of gas. How much gas should he expect to use for a 3000-mile
erma4kov [3.2K]
750 bc u dived 3000 by 4 bc 4 is per ever 100
3 0
2 years ago
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If n(A-B)=18,n(AuB)=70 and n(AnB)=25 then find n(B)
svp [43]

n(A-B) denotes elements which are in A but not in B

n(Au B) denotes elements in A and B

n(AnB) denotes elements that are common in A and B

Now I will add one more set

n(B-A) which denotes elements in B but not in A

So, n(AuB) = n(A-B) + n( B-A) +n(AnB)

70 = 18 +n(B-A) + 25

70 = 43 + n(B-A)

n(B-A) = 70-43

n(B-A) = 27

So, n(B) = n( B-A) + n( AnB)

= 27+25

= 52

4 0
2 years ago
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