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2 years ago

6

Vince weighs 160 pounds and his friend nadir weighs 140 nadir calculated that his weight on another planet would be about 56lb a

pproximately what would Vince weigh on the other planet

2 answers:

zzz [600]2 years ago

7 0

His weight would be 64lb

chubhunter [2.5K]2 years ago

3 0

Vince would weigh 64 pounds

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A random survey of the quality of city park is taken.sixty-five percent of the people surveyed were pleased with the condition o

Maurinko [17]

Answer:

280 people

Step-by-step explanation:

Given that 65% of people surveyed were pleased with condition of the park.

Given that those pleased were 182 people, then finding the total number of people surveyed will be;

65%= 182 people

100%= ?--------------------cross multiply

$\frac{65}{100} *x=182\\\\\\65x=18200\\\\\\x=\frac{18200}{65} \\\\\\x=280$

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Compute the requested value. Choose the correct answer.

Fiesta28 [93]

Original price of the item = $14.95

Price after discount = $13.79

Discount offered = original price - price after discount = 14.95- 13.79 = $1.16

Now let us find the percentage of discount offered.

Percentage discount is given by the formula:

$Percentage discount = \frac{MP-SP}{MP}*100$

Where MP= Marked price= original price

SP= selling price= price after discount

$Percentage discount = \frac{1.16}{14.95}*100$

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32.15 is written correctly in EXPANDED FORM using FRACTIONS

marshall27 [118]

Answer:

Step-by-step explanation:

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2 years ago

Greg is trying to solve a puzzle where he has to figure out two numbers, x and y. Three less than two-third of x is greater than

Fittoniya [83]

Inequation 1:

$\frac{2}{3}x-3 \geq y$

to plot the pairs (x, y) for which the inequation holds, draw the line $y=\frac{2}{3}x-3$

then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.

we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.

inequation 2:

$y+ \frac{2}{3}x\ \textless \ 4$

$y\ \textless \ - \frac{2}{3} x+ 4
$

draw the lines

i) $y=\frac{2}{3}x-3$ use points (0, -3), (3, -1)

ii) $y=- \frac{2}{3} x+ 4$ use points ( 0, 4), (3, 2)

let's use the point P(3, 3) to see what region of the lines need to be coloured:

$\frac{2}{3}x-3 \geq y$ ;
$\frac{2}{3}(3)-3 \geq 3$
$2-3 \geq 3$ , not true so we color the region not containing this point

$y+ \frac{2}{3}x\ \textless \ 4$
$(3)+ \frac{2}{3}(3)\ \textless \ 4$
$3+ 5\ \textless \ 4$ not true, so we color the region not containing the point (3, 3)

The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.

4 0

2 years ago