The given line segment has a midpoint at (3, 1). What is the equation, in slope-intercept form, of the perpendicular bisector of
the given line segment? y = x y = x – 2 y = 3x y = 3x − 8
2 answers:
Answer:
Step-by-step explanation:
I think the attached photo supports for your question
Here is my anser:
We need to find the slope of the of and from the graph, we see that if x increases from 2 to 4, y decreases from 4 to -2. Thus, the slope of the blue line is : = -3
But the slope of the perpend. bisector of the blue line is the negative reciprocal of -3, or m= 1/3.
Let's find the slope-intercept form of this bisector. We need to determine b in y=mx+b. Referring to the midpoint of the blue line, x= 3; y= 1; and m=1/3. Then
y=mx+b becomes 1=(1/3)(3) + b. Solving for b: 1=1+b. Then b=0.
Thus, the equation of the perpendicular bisector of the blue line through (3,1) is y=mx + b, or y=(1/3)x + 0, or y=x/3.
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Answer:
The claim that all ages have purchase rates proportional to their driving rates is false.
Step-by-step explanation:
The complete question is:
A random sample of 160 car accidents are selected and categorized by the age of the driver determined to be at fault. The results are listed below. The age distribution of drivers for the given categories is 18% for the under 26 group, 39% for the 26-45 group, 31% for the 45-65 group, and 12% for the group over 65. Calculate the chi-square test statistic used to test the claim that all ages have crash rates proportional to their driving rates.
Age >26 26-45 46-65 45<
Drivers 66 39 25 30
A) 95.431
B)101.324
C)85.123
D)75.101
Solution:
In this case we need to test whether there is sufficient evidence to warrant rejection of the claim that all ages have crash rates proportional to their driving rates.
A Chi-square test for goodness of fit will be used in this case.
The hypothesis can be defined as:
<em>H₀</em>: The observed frequencies are same as the expected frequencies.
<em>Hₐ</em>: The observed frequencies are not same as the expected frequencies.
The test statistic is given as follows:
The values are computed in the table.
The test statistic value is 75.10.
The degrees of freedom of the test is:
n - 1 = 4 - 1 = 3
Compute the p-value of the test as follows:
p-value < 0.00001
*Use a Chi-square table.
p-value < 0.00001 < α = 0.05.
So, the null hypothesis will be rejected at any significance level.
Thus, there is sufficient evidence to warrant rejection of the claim that ages have crash rates proportional to their driving rates.
Answer:
x=
Step-by-step explanation:
Step 1: Multiply both sides by x,
gx=−c+x
Step 2: Add -x to both sides.
gx+−x=−c+x+−x
gx−x=−c
Step 3: Factor out variable x.
x(g−1)=−c
Step 4: Divide both sides by g-1.
x=
Hope this helps!
Answer:
The fraction of the students who failed to went partying =
Step-by-step explanation:
Let total number of students = 100
No. of students partied are twice the no. of students who not partied.
⇒ No. of students partied = 2 × the no. of students who are not partied
No. of students partied before the exam = 20 % of total students
⇒ No. of students partied before the exam = × 100
⇒ No. of students partied before the exam = 20
No. of students who not partied before the exam =
Thus the fraction of the students who failed to went partying =