The given line segment has a midpoint at (3, 1). What is the equation, in slope-intercept form, of the perpendicular bisector of
the given line segment? y = x y = x – 2 y = 3x y = 3x − 8
2 answers:
Answer:
Step-by-step explanation:
I think the attached photo supports for your question
Here is my anser:
We need to find the slope of the of and from the graph, we see that if x increases from 2 to 4, y decreases from 4 to -2. Thus, the slope of the blue line is : = -3
But the slope of the perpend. bisector of the blue line is the negative reciprocal of -3, or m= 1/3.
Let's find the slope-intercept form of this bisector. We need to determine b in y=mx+b. Referring to the midpoint of the blue line, x= 3; y= 1; and m=1/3. Then
y=mx+b becomes 1=(1/3)(3) + b. Solving for b: 1=1+b. Then b=0.
Thus, the equation of the perpendicular bisector of the blue line through (3,1) is y=mx + b, or y=(1/3)x + 0, or y=x/3.
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