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2 years ago

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How does the range of g (x) = StartFraction 6 Over x EndFraction compare with the range of the parent function f (x) = StartFrac

tion 1 Over x EndFraction?
The range of both f(x) and g(x) is all real numbers
The range of both f(x) and g(x) is all nonzero real numbers
The range of f(x) is all real numbers, the range of g(x) is all real numbers except 6
The range of f(x) is all nonzero real numbers, the range of g(x) is all real numbers except 6

2 answers:

xz_007 [3.2K]2 years ago

8 0

Answer:

B

Step-by-step explanation:

Lerok [7]2 years ago

3 0

Answer: Option: (B) The range of both f(x) and g(x) is all nonzero real numbers is correct.

Step-by-step explanation: ..................Because I said so............................

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Arrange the entries of matrix A in increasing order of their cofactors values

givi [52]

To find the cofactor of

$A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]$

We cross out the Row and columns of the respective entries and find the determinant of the remaining $2\times 2$ matrix with the alternating signs.

$Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|$

$Ac_{11}=4\times 1- -1\times 2$

$Ac_{11}=4+ 2$

$Ac_{11}=6$

$Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|$

$Ac_{12}=-(-7\times 1- -1\times -8)$

$Ac_{12}=-(-7- 8)$

$Ac_{12}=15$

$Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|$

$Ac_{21}=-(5\times 1- 3\times 2)$

$Ac_{21}=-(5-6)$

$Ac_{21}=1$

$A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|$

$Ac_{23}=-(7\times 2 -8\times 5)$

$Ac_{23}=-(14-40)$

$Ac_{23}=26$

$A_c{31}=\left|\begin{array}{ccc}5&3\\4&-1\end{array}\right|$

$Ac_{31}=5\times -1 -4\times 3$

$Ac_{31}=-5-12$

$Ac_{31}=-17$

$A_c{33}=\left|\begin{array}{ccc}7&5\\-7&4\end{array}\right|$

$Ac_{33}=7\times 4- -7\times 5$

$Ac_{33}=28+35$

$Ac_{33}=63$

Therefore in increasing order, we have;

$Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63$

7 0

2 years ago

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The endpoints of JK are J(–25, 10) and K(5, –20). What is the y-coordinate of point L, which divides JK into a 7:3 ratio? a. –16

Andrews [41]

let's say the point dividing JK is say point P, so the JK segment gets split into two pieces, JP and PK

$\bf ~~~~~~~~~~~~\textit{internal division of a line segment} \\\\\\ J(-25,10)\qquad K(5,-20)\qquad \qquad \stackrel{\textit{ratio from J to K}}{7:3} \\\\\\ \cfrac{J~~\begin{matrix} P \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} P \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~K} = \cfrac{7}{3}\implies \cfrac{J}{K} = \cfrac{7}{3}\implies3J=7K\implies 3(-25,10)=7(5,-20)\\\\[-0.35em] ~\dotfill$

$\bf P=\left(\frac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \frac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)\\\\[-0.35em] ~\dotfill\\\\ P=\left(\cfrac{(3\cdot -25)+(7\cdot 5)}{7+3}\quad ,\quad \stackrel{\textit{y-coordinate}}{\cfrac{(3\cdot 10)+(7\cdot -20)}{7+3}}\right) \\\\\\ P=\left( \qquad ,\quad \cfrac{30-140}{10} \right)\implies P=\left(\qquad ,~~\cfrac{-110}{10} \right)\implies P=(\qquad ,\quad -11)$

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2 years ago

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Explain how to compare 0.7 and 5/8.

Lesechka [4]

You divide 5/8 the answer I get I will look for the largest number:5÷8=0.625 then I compare your answer is 0.7,0.yet.

Hope it helped u

7 0

2 years ago

1.09g/mL to lbs/gal <br><br> Please show how to solve it too

GaryK [48]

For this case we must take into account the following conversions:

1 pound = 450 grams

1 mL = 0.00026 gallons

We apply the transformation of units to the following expression:

$1.09\frac{g}{mL}$

We have then:

$(1.09\frac{g}{mL})(\frac{1}{450}\frac{lbs}{g}) = 0.0024\frac{lbs}{mL}$

$(0.0024\frac{lbs}{mL})(\frac{1}{0.00026}\frac{mL}{gal}) = 9.23\frac{lbs}{gal}$

Answer:

Applying both transformations to the given expression we have:

$9.23\frac{lbs}{gal}$

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2 years ago

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Which transformations can be used to carry ABCD onto itself? The point of rotation is (3, 2). Check all that apply.

Shtirlitz [24]

A and B.

This is because X=3 directly cuts the rectangle in half so the reflection will just look like the original shape.

And for shapes that have 2 lines of symmetry any 180 degree rotation will end up aligning with one of these axis and become indistinguishable from the original shape.

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2 years ago

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