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Jlenok [28]
2 years ago
13

How does the range of g (x) = StartFraction 6 Over x EndFraction compare with the range of the parent function f (x) = StartFrac

tion 1 Over x EndFraction?
The range of both f(x) and g(x) is all real numbers
The range of both f(x) and g(x) is all nonzero real numbers
The range of f(x) is all real numbers, the range of g(x) is all real numbers except 6
The range of f(x) is all nonzero real numbers, the range of g(x) is all real numbers except 6
Mathematics
2 answers:
xz_007 [3.2K]2 years ago
8 0

Answer:

B

Step-by-step explanation:

Lerok [7]2 years ago
3 0

Answer: Option: (B) The range of both f(x) and g(x) is all nonzero real numbers is correct.

Step-by-step explanation: ..................Because I said so............................

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A random sample of 250 students at a university finds that these students take a mean of 15.2 credit hours per quarter with a st
Orlov [11]

Answer:

95% confidence interval for the mean credit hours taken by a student each quarter is [14.915 hours , 15.485 hours].

Step-by-step explanation:

We are given that a random sample of 250 students at a university finds that these students take a mean of 15.2 credit hours per quarter with a standard deviation of 2.3 credit hours.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                          P.Q. = \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample credit hours per quarter = 15.2 credit hours

             s = sample standard deviation = 2.3 credit hours

             n = sample of students = 250

             \mu = population mean credit hours per quarter

<em>Here for constructing 95% confidence interval we have used One-sample t test statistics as we know don't about population standard deviation.</em>

So, 95% confidence interval for the population mean, \mu is ;

P(-1.96 < t_2_4_9 < 1.96) = 0.95  {As the critical value of t at 249 degree of

                                        freedom are -1.96 & 1.96 with P = 2.5%}  

P(-1.96 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u><em>95% confidence interval for</em></u> \mu = [ \bar X-1.96 \times {\frac{s}{\sqrt{n} } } , \bar X+1.96 \times {\frac{s}{\sqrt{n} } } ]

                  = [ 15.2-1.96 \times {\frac{2.3}{\sqrt{250} } } , 15.2+1.96 \times {\frac{2.3}{\sqrt{250} } } ]

                  = [14.915 hours , 15.485 hours]

Therefore, 95% confidence interval for the mean credit hours taken by a student each quarter is [14.915 hours , 15.485 hours].

<em>The interpretation of the above confidence interval is that we are 95% confident that the true mean credit hours taken by a student each quarter will be between 14.915 credit hours and 15.485 credit hours.</em>

8 0
2 years ago
What is the surface area of this right rectangular prism?<br><br> Enter your answer in the box.
antoniya [11.8K]

Answer:

The surface area is 22m

4 0
2 years ago
Given: △PTC
Natalka [10]
Given the the two angles find the missing angle of P which is 30 degrees.

Since angle P and C are identical their sides are congruent.

The hypotenuse, the largest side is PC because it corresponds to angle T

Using Pythagorean Theorem
a^2 + b^2 = c^2

(PT)^2 + (CT)^2 = (PC)^2
Given that PT is 4 and knowing PT and CT are congruent we can rewrite this
(4)^2 + (4)^2 = (PC)^2
PC = rad(32)

Someone fact check plz
6 0
2 years ago
Read 2 more answers
Which of the following options have the same value as 65%, percent of 20?
aev [14]

Answer:

13

Step-by-step explanation:

You find out what is one percent then multiply from there

3 0
2 years ago
Read 2 more answers
Find the total area for the regular pyramid.<br> T. A. =
Volgvan

Answer:

The answer to your question is Superficial area = 144 + 36√3

Step-by-step explanation:

Process

1.- Calculate the area of the base

Area = base x height / 2

-Calculate the height using the Pythagorean theorem

        h² = 12² - 6²

        h² = 144 - 36

        h² = 108

        h = √108

        108  2

          54  2

          27  3

            9  3

             3  3

             1

         h = 6√3

Area = 12 x 6√3/2

Area = 36√3 u²

2.- Calculate the area of the superficial 3 triangles

Area = base x height / 2

-Calculate the height using the Pythagorean theorem

         h² = 10² - 6²

         h² = 100 - 36

         h² = 64

         h = 8

Area = 12 x 8/2

Area = 48 u²

Total area = 3(48) + 36√3

                 = 144 + 36√3

3 0
2 years ago
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