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vovikov84 [41]
2 years ago
14

Solve the formula for the specified variable. D=1/2fk for f f=

Mathematics
1 answer:
Andreyy892 years ago
4 0
We are asked to solve the formula D=\frac{1}{2}fk for f. Starting off, we can divide both sides by k, so we are left with only the variable f on the right-hand side. Next, we need to multiply the reciprocoal of \frac{1}{2}, which is 2 to both sides. This gives us 2*\frac{D}{k}=f, which, when simplified, gives us \boxed{f=\frac{2D}{k}}. Hope this helped and have a phenomenal day!
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A dartboard has 10 equally sized slices numbered from 1 to 10. Some are grey and some are white. The slices numbered 1,2 ,3 ,5 ,
hram777 [196]

Answer:

P(X) is 7/10

P(not X) is 3/10

Step-by-step explanation:

The total is 10 so thats ur denominator

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Hope this helps

5 0
2 years ago
An experiment was performed to compare the wear of two different laminated materials. Twelve pieces of material 1 were tested by
GenaCL600 [577]

Answer:

At 0.05 level of significance, the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

Step-by-step explanation:

We hypothesize that mean difference between abrasive wear of material 1 and material 2 is greater than 2.

So we write the null hypothesis H_0 : \mu_1 - \mu_2 >2,

and the alternative hypothesis H_1: \mu_1 - \mu_2 \leq 2.

We will find the T-score as well as the p-value. If the p-value is less than the level of significance, we will reject the null hypothesis, i.e. we will conclude that the abrasive wear of material 1 is less than that of material 2. Otherwise, we will accept the null hypothesis.

Since the variance is unknown and assumed to be equal, we will use the pooled variance

s_p^2 = \frac{(n_1-1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2} = 20.05,

where n_1 = 12, n_2 =10, s_1 =4, s_2 = 5.

The mean of material 1 and material 2 are \mu_1 =85, \mu_2=81 respectively and mean difference d is equal to 4. The hypothesize difference d_0 is equal to 2.

To find the T-score, we use the following formula

T = \frac{d - d_0}{\sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2} }}

Substituting all the values into the T-score formula gives us T = 1.04, and the respective p-value is equal to 0.31. This means we have enough statistical evidence not to reject the null hypothesis, and at 5% significance level, the abrasive wear of material 1 exceeds that of material 2 by more than 2 units.

6 0
1 year ago
All I need is this answer,please help!!
il63 [147K]
Hello there,

There is a total of 40 animals in that in 10 zebras, 10 lions, 10 elephants, and 10 monkeys.
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I hope this helps!
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