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Oksi-84 [34.3K]
1 year ago
6

(c) Assume this is a simple random sample of U.S. women. Use the Empirical Method to estimate the probability that a woman has m

ore than six children. Round your answer to four decimal places.

Mathematics
1 answer:
ella [17]1 year ago
6 0

Complete Question

The complete question is shown on the first uploaded image

Answer:

p(X> 6 ) = 0.01132 + 0.01672 = 0.0280

           

Step-by-step explanation:

The probability that the US woman would have more than six children is equal to the probability that she would have children that are equal to 7 or that she would that she would have children equal to 8 or more as shown on the table in the question

Now representing this mathematically we have

                     p(X > 6) = p(x =7 ) + p(x = 8 or more)

    From the table the p(x = 7 ) = \frac{523}{46165} = 0.01132

     And the p(x= 8 or more ) = \frac{772}{46165} = 0.01672

Hence  p(X> 6 ) = 0.01132 + 0.01672 = 0.0280

           

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A red candle is 8 inches tall and burns at a rate of 7/10 inch per hour. A blue candle is 6 inches tall and burns at a rate of 1
kogti [31]

Answer:

The heights are the same after 4 hours.

Step-by-step explanation:

The red candle burns at a rate of 7/10 inches per hour. In t hours, (7/10)t inches have burned. The height of the candle after t hours is 8 - (7/10)t.

The blue candle burns at a rate of 1/5 inch per hour. In t hours, (1/5)t inches have burned. The height of the candle after t hours is 6 - (1/5)t.

You need to find the time, t, when their heights are equal.

8 - (7/10)t = 6 - (1/5)t

Multiply both sides by 10 (the LCD).

80 - 7t = 60 - 2t

-5t = -20

t = 4

The heights are the same after 4 hours.

3 0
2 years ago
If pq=9 and qr=28, find PR
Ksenya-84 [330]
PQ = 9
QR = 28

Note, there is a Q in each line

Combine the two lines: PQ + QR = PR

plug in the numbers to corresponding variables

9 + 28 = PR

PR = 37

hope this helps
8 0
2 years ago
HELP! A daycare purchases two type of snacks, granola bars and fruit rolls. One week, they purchase 10 packs of granola bars and
ch4aika [34]
10x+6y=152
5x+3y=76
7x+12y=200
-20x-12y=-304
-13x=-104
x=8
40+3y=76
3y=36
y=12
There are 8 granola bars in a pack and 12 fruit rolls in a pack
5 0
2 years ago
Read 2 more answers
Your cell phone plan charges a base charge each month plus a charge per daytime minute of usage and December used 510 daytime mi
algol13

Answer:

In February, 423 daytime minutes is used

Step-by-step explanation:

Let the base plan charges be x

And cost per daytime minute be y

In December,

x  + 510y =  92.25------------------(1)

In January,

x + 397y = 77.56---------------------(2)

Subtracting eq(2) from eq(1)

x  + 510y =  92.25

x + 397y = 77.56

-------------------------------

0  + 113y = 14.69

-------------------------------

y = \frac{14.69}{113}

y =  0.13----------------------------------(3)

Substituting (3) in (1)

x  + 510(0.13) =  92.25

x + 66.3 = 92.25

x = 92.25 - 66.3

x = 25.95

So In February

base plan  + (daytime minute)(cost per daytime minute) = 80.9

25.95 + (daytime minute)(0.13) = 80.9

(daytime minute)(0.13) = 80.9 - 25.95

(daytime minute)(0.13) = 54.95

(daytime minute) =\frac{54.95}{0.13}

daytime minutes = 422.69

daytime minute  \approx 423

3 0
2 years ago
If quadrilateral PQRS is a rectangle, then which of the following is true?
brilliants [131]

∠STP ≅ ∠QTR is the True statement ⇒ answer C

Step-by-step explanation:

In any rectangle

1. Each two opposite sides are equal and parallel

2. The measure of its vertex angles is 90°

3. The two diagonals are equal

Now lets find the true statements

∵ PQRS is a rectangle

∴ PS = QR ⇒ opposite sides

∴ PQ = SR ⇒ opposite sides

∴ PR = QS ⇒ diagonals

A.  ∠PSQ ≅ ∠QSR

∵ The diagonals of the rectangle do not bisect the vertex angles

∴ AQ does not bisect angle S

∴  m∠PSQ ≠ m∠QSR

∴  ∠PSQ not congruent ∠QSR

∠PSQ ≅ ∠QSR ⇒ False

B. segment SR ≅ segment RQ

∵ SR and RQ are two adjacent sides

∵ The adjacent side in the rectangle not equal

∴ SR ≠ QR

∴ segment SR not congruent to segment RQ

segment SR ≅ segment RQ ⇒ False

C. ∠STP ≅ ∠QTR

∵ PR intersects QS at point T

∴ m∠STP = m∠QTR ⇒ vertically opposite angles

∴ ∠STP ≅ ∠QTR

∠STP ≅ ∠QTR ⇒ True

D. segment PS ≅ segment PR

∵ PS is a side in the rectangle

∵ PR is a diagonal in the rectangle

∵ The side of the rectangle not equal the diagonal of the rectangle

∴ PS ≠ PR

∴ segment PS not congruent to segment PR

segment PS ≅ segment PR ⇒ False

∠STP ≅ ∠QTR is the True statement

Learn more:

You can learn more about rectangle in brainly.com/question/6594923

#LearnwithBrainly

8 0
2 years ago
Read 2 more answers
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