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lesya692 [45]
1 year ago
11

On a state map, a cartographer plots Geocity at coordinates (5, 8) and Shapetown at coordinates (11, 16). How far is it from Geo

city to Shapetown?
Mathematics
1 answer:
Eddi Din [679]1 year ago
7 0
We can solve for the distance between Geocity to Shapetown using the formula for the distance between two points which is shown below:
d² = (x2-x1)²+(y2-y1)²
Such as we have two points:
Geocity (5,8)
Shapetown (11,16)

Solving for the distance, we have:
d² = (11-5)² + (16-8)²
d² = 6² + 8²
d = 10

The answer is 10 units.
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Chapter 7 of the Jiuzhang suanshu presents a problem of two linear equations involving acres of land and their respective prices
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Answer: 33.041666

Step-by-step explanation:

Given: The translated equation : 300x+y = 10000

To find the value of x if y = 87.5, we need to substitute the value of y in the given translated equation, we will get

300x+87.5 = 10000

Subtract 87.5 from both the sides , we get

300x=9912.5

Now, divide 300 on both the sides, we get

x=\frac{9912.5}{300}\\\\\Rightarrow x=33.041666666

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What did they call the bug that the astronauts brought back from the moon?
ludmilkaskok [199]
A lunatic (haha) .-.

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2 years ago
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How long will it take before twenty percent of our 1,000-gram sample of uranium-235 has decayed? [See Section 6.6 Example 13] Th
horsena [70]

Answer:

From what I can see of the problem, you CANNOT solve for the half-life of U 235 AND then solve for the length of time to determine the 20% decay.

U-235 half-life is 704,000,000 years. (Wikipedia)

The elapsed time formula = half-life * [log (Beginning Amount / ending amount) / log 2]

elapsed time = 7.04 x 10^8 * [log (100 % / 80%) / log 2]

elapsed time =7.04 x 10^8 *  [log (1.25) / .30103]

elapsed time =7.04 x 10^8 *  [0.096910 / .30103]

elapsed time = 7.04 x 10^8 *  0.321928047

elapsed time = 226,637,000 years

Step-by-step explanation:

8 0
2 years ago
P(vanilla) =0.3 P(sundae)=0.2 P(vanilla and sundae) =0.15 find the probability that a customer ordered vanilla ice cream given t
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Answer:

0.75

Step-by-step explanation:

P(A | B) = P(A and B) / P(B)

P(vanilla | sundae) = P(vanilla and sundae) / P(sundae)

P(vanilla | sundae) = 0.15 / 0.2

P(vanilla | sundae) = 0.75

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The probability is 1% that an electrical connector that is kept dry fails during the warranty period of a portable computer. If
rodikova [14]

Answer:

1.4% of connectors fail during the warranty period.

Step-by-step explanation:

We have these following probabilities:

A 90% probability that a connector is kept dry.

A 10% probability that a connectors is wet.

If a connector is dry, an 1% probability of failling.

If a connector is wet, a 5% probability of failling.

What proportion of connectors fail during the warranty period?

This is 1% of 90% and 5% of 10%. So

P = 0.01*0.9 + 0.05*0.1 = 0.014

1.4% of connectors fail during the warranty period.

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