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Gennadij [26K]
2 years ago
14

829.9 to the nearest whole number

Mathematics
2 answers:
anzhelika [568]2 years ago
7 0

when rounding numbers: if it's four or less, you round down. if it's five or more, you round up. 9 is bigger than 4, so the nearest whole number is 830.

Arte-miy333 [17]2 years ago
5 0
The answer would be 830!
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Answer:

a=-\frac{b}{2x}

Step-by-step explanation:

The equation of a quadratic function is given as:

ax² + bx + c = 0

where a, b and c are the coefficient in the quadratic equation.

The axis of symmetry of the quadratic equation is given as:

x=-\frac{b}{2a}

To get the equation for a, we have to make a the subject of formula:

x=-\frac{b}{2a}\\\\multiply\ both\ sides\ by \ 2a:\\\\x*2a=-\frac{b}{2a}*2a\\\\2ax=-b\\\\Divide\ through\ by\ 2a\\\\2ax/2a=-b/2a\\\\a=-\frac{b}{2x}

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svp [43]

We have to find the potential solutions to 2 ln x = 4 ln 2 from least to greatest.

Using the properties of ln function.

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taking antilog on both the sides, we get

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or

y=2((x-\dfrac{1}{2})^2)-\dfrac{27}{2}

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y=3(x-2)^2-(x-5)^2\\\\=3(x^2+4-4x)-(x^2+25-10x)\\\\=3x^2+12-12x-x^2-25+10x\\\\=2x^2-2x-13\\\\=2(x^2-x-\dfrac{13}{2})\\\\=2(x^2-x+\dfrac{1}{4}-\dfrac{1}{4}-\dfrac{13}{2})\\\\=2((x-\dfrac{1}{2})^2-\dfrac{1+26}{4})\\\\=2((x-\dfrac{1}{2})^2-\dfrac{27}{4})=2((x-\dfrac{1}{2})^2)-\dfrac{27}{2}

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