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2 years ago

829.9 to the nearest whole number

2 answers:

7 0

when rounding numbers: if it's four or less, you round down. if it's five or more, you round up. 9 is bigger than 4, so the nearest whole number is 830.

Arte-miy333 [17]2 years ago

5 0

The answer would be 830!

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The axis of symmetry for a quadratic equation can be found using the formula x equals StartFraction negative b Over 2 a EndFract

alexandr402 [8]

Answer:

$a=-\frac{b}{2x}$

Step-by-step explanation:

The equation of a quadratic function is given as:

ax² + bx + c = 0

where a, b and c are the coefficient in the quadratic equation.

The axis of symmetry of the quadratic equation is given as:

$x=-\frac{b}{2a}$

To get the equation for a, we have to make a the subject of formula:

$x=-\frac{b}{2a}\\\\multiply\ both\ sides\ by \ 2a:\\\\x*2a=-\frac{b}{2a}*2a\\\\2ax=-b\\\\Divide\ through\ by\ 2a\\\\2ax/2a=-b/2a\\\\a=-\frac{b}{2x}$

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2 years ago

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The Revenue for the week is $2000, and labor cost consists of two workers earning $8 per hour who work 40 hours each, what is la

kkurt [141]

8*40 = 320 * 2 = $640 for the 2 workers

640/2000 = 0.32

labor cost is 32% of the revenue

8 0

2 years ago

List the potential solutions to 2 ln x = 4 ln 2 from least to greatest.

svp [43]

We have to find the potential solutions to $2 ln x = 4 ln 2$ from least to greatest.

Using the properties of ln function.

$a \times ln b = ln b^{a}$

Therefore, we get

$ln x^{2} = ln 2^{4}$

$ln x^{2} = ln 16$

taking antilog on both the sides, we get

$x^{2} = 16$

So, $x = \pm 4$

Therefore, the potential solutions to 2 ln x = 4 ln 2 from least to greatest is -4 and 4.

3 0

2 years ago

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Which equation is y = 3(x – 2)2 – (x – 5)2 rewritten in vertex form? Y = 3 (x minus seven-halves) squared minus StartFraction 27

densk [106]

Answer: y = 2 (x minus one-half) squared minus StartFraction 27 Over 2 EndFraction

$y=2((x-\dfrac{1}{2})^2)-\dfrac{27}{2}$

Step-by-step explanation:

Vertex form of equation : $f (x) = a(x - h)^2 + k,$ where (h, k) is the vertex of the parabola.

$y=3(x-2)^2-(x-5)^2\\\\=3(x^2+4-4x)-(x^2+25-10x)\\\\=3x^2+12-12x-x^2-25+10x\\\\=2x^2-2x-13\\\\=2(x^2-x-\dfrac{13}{2})\\\\=2(x^2-x+\dfrac{1}{4}-\dfrac{1}{4}-\dfrac{13}{2})\\\\=2((x-\dfrac{1}{2})^2-\dfrac{1+26}{4})\\\\=2((x-\dfrac{1}{2})^2-\dfrac{27}{4})=2((x-\dfrac{1}{2})^2)-\dfrac{27}{2}$

Hence, the vertex form of the equation is $y=2((x-\dfrac{1}{2})^2)-\dfrac{27}{2}$

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2 years ago

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Alona [7]

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