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EleoNora [17]
1 year ago
12

The Rotation R maps all 60° about O the center of the regular hexagon. State the image of B for the following rotation.

Mathematics
2 answers:
Andru [333]1 year ago
7 0
It is B. Since each angle is 60 degrees, if you rotate B counterclockwise 6 times, it means that you rotated B 360 degrees. Therefore, the image of B would be B.
AleksAgata [21]1 year ago
6 0

Answer:

B will be at same place after all six rotations.

Step-by-step explanation:

If rotation maps to 60^{\circ}

Then [tex]R^6[tex] means six rotations .

The given B after one rotation will shift in place of A

After second rotation will shift in place of F

After third rotation will shift in place of E

After fourth rotation will shift in place of D

After fifth rotation will shift in place of C

After sixth rotation will shift in place of B itself.

Therefore, B will come back to same place after all the required rotations.

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Step-by-step explanation:

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2 years ago
PLEASE HELP MATH EXPAND LOG
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Answer:

½log3 + ½logx

Step-by-step explanation:

½(log(3x))

½(log3 + logx)

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8 0
1 year ago
The marketing manager of a branch office of a local telephone operating company wants to study the characteristics of residentia
charle [14.2K]

Answer:

No. There is not enough evidence to support the claim that the population standard deviation is different from $12.

Step-by-step explanation:

The null hypothesis is that the true standard deviation is 12.

The alternative hypothesis is that the true standard deviation differs from 12.

We can state:

H_0: \sigma=12\\\\H_a: \sigma\neq12

The significance level is 0.10.

The sample size is n=15, so the degrees of freedom are:

df=n-1=15-1=14

The sample standard deviation is 9.25.

The test statistic is

T=(n-1)(s/\sigma_0)^2=14*(9.25/12)^2=14*0.77^2=14*0.59=8.32

The critical values for rejecting the null hypothesis are:

\chi_{0.025,13}=5.00875\\\\\chi_{0.975,13}=24.7356

As T=8.32 is within the acceptance region (5.01, 24.74), the null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the population standard deviation is different from $12.

8 0
1 year ago
The distance from Mason's house to Kevin's house is about 5 × 105 inches. The distance from Mason's house to Chloe's house is ab
olga nikolaevna [1]

Answer:

Distance from Mason's house to Chloe's house is 160 as great as the distance from Mason's to Kevin's house.

Step-by-step explanation:

Let the distance from Mason's house to Chloe's house is x times as great as the distance from Mason's to Kevin's house.

Distance from Mason's house to Kevin's house= 5 \times 10^5 inches.

Distance from Mason's house to Chloe's house =8 \times 10^7 inches

ATQ

8 \times 10^7= x \times 5 \times 10^5 \\\frac{8 \times 10^7}{5 \times 10^5}=x\\160=x

So, distance from Mason's house to Chloe's house is 160 times as great as the distance from Mason's to Kevin's house.

Hence distance from Mason's house to Chloe's house is 160 as great as the distance from Mason's to Kevin's house.

6 0
1 year ago
List 3 rational numbers between 3 and 3.9
antiseptic1488 [7]

Answer:

its not showing up

Step-by-step explanation:

5 0
1 year ago
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