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Eduardwww [97]
1 year ago
13

Which number line correctly shows 0.8 + 0.3? A number line going from 0 to 1.3 in increments of 0.01. An arrow goes from 1.1 to

0.3 and from 0.3 to 0. A number line going from 0 to 1.3 in increments of 0.01. An arrow goes from 0 to 0.8 and from 0.8 to 1.1. A number line going from 0 to 1.3 in increments of 0.01. An arrow goes from 0 to 0.8, and then backwards from 0.8 to 0.5. A number line going from 0 to 1.3 in increments of 0.01. An arrow goes from 0.3 to 1.1 and then backwards from 1.1 to 0.8.

Mathematics
2 answers:
steposvetlana [31]1 year ago
7 0

Answer:

the second number line in the second row OR The number line D in the attached image

Step-by-step explanation:

Lets start solving the question.

(For ease of understanding each line i have labeled them please see the attachment to relate my explanation)

first read the question it i mentioned that which number line currently shows 0.8+0.3.

After reading the question it is clear that which ever line will represent it will be the addition of 08.+0.3.

here please take a note that we are dealing with a number line hence the sign also matters.

Now lets start analyzing lines one by one.To make it easy i have attached an image where i have labeled the lines as A,B,C,D,E,and F for the ease  of understanding.

so take the first line A into consideration,

its starting from 0.3 and ending at 0 means its decrementing you can also determine it with the direction. any line that originates from the origin and goes to the right shows increment and addition and the lines that originates from origin and goes to the left shows decrement.

so here we can easily all those lines which are showing a leftward directions as it is decrementing and we want a line that increments 0.8+0.3

so now th lines A,B,F and H can be skipped.

We are done with analyzing line A, line B is skipped and now lets start with C.

here the line start from 0 and ends at 0.8 so it cant be the line as 0.8+0.3 yields 0.11.

so line C can't be the correct one.

Now lets consider the next line that is D.

here it starts at 0.8 and ends at 0.11 means exactly showing an increment of 0.3 also its showing a positive directions as its heading to the right.

so this is the line that correctly shows 0.8+0.3.

Now consider line E it cant be the correct line as its showing only 0 to 0.8.

and now the line that will confuse you is line G.

it starts at 0.3 and ends at 0.11 here there is increment of 0.8 though it seems like correct but it cant be the line showing 0.8+0.3 as we have to select the line that originates at 0.8 and shows an increment of 0.3 and not the one which originates at 0.3 and ends at 0.11 showing an increment of 0.8.

Also the question itself is asking 'LINE' and not 'LINES' so you can take such minute things also into Consideration for avoiding any kind of confusion.

I hope this will help  you.

WARRIOR [948]1 year ago
6 0

Answer:

B

Step-by-step explanation:

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Options:

A. Both the Highlands and the Lowlands data points are evenly distributed around the center.

B. Both the Highlands and the Lowlands data points are clustered toward the left of the plot.

C. The Highlands data points are evenly distributed around the center, while the Lowlands data points are clustered toward the left of the plot.

D. The Highlands data points are clustered toward the left of the plot, while the Lowlands data points are evenly distributed.

Answer:

B. Both the Highlands and the Lowlands data points are clustered toward the left of the plot.

Step-by-step Explanation:

From the dot plots displaying rainfall totals for highland and lowland areas as shown in the diagram attached below, we can clearly observe that most of the dots on the plot tend to be more concentrated towards the left of the plot, compared to the concentration of dots toward the right of the plot.

Invariably, we can infer that data points for lowlands and Highlands are clustered toward the left of the plot.

Therefore, the statement that is true, comparing the shapes of the dot plot is B. "Both the Highlands and the Lowlands data points are clustered toward the left of the plot."

7 0
1 year ago
To support a tree damaged in a storm, a 12-foot wire is secured from the ground to the tree at a point 10 feet off the ground. T
Nina [5.8K]
Given:
<span>12-foot wire is secured from the ground to the tree at a point 10 feet off the ground.
The tree meets the ground at a right angle. 

When you visualize the scenario, the 12 foot wire would be the measure of the hypotenuse and the 10 feet off the ground will be the short leg or opposite. The long leg or adjacent is unknown. 

We need to solve for sine theta because the value of hypotenuse and opposite is given.

sin </span>θ = opposite / hypotenuse
sin θ = 10 feet / 12 feet
sin θ = 0.833
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The wire would meet the ground at approximately 56° angle.

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1 year ago
Li wants to add these items to her suitcase: a hairdryer (1.25 lb), a hand-held video game (0.6 lb), an extra video game (0.25 l
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Answer:

She will leave an extra video game which weighs 0.25lb

Step-by-step explanation:

Li wants to add these items to her suitcase: a hairdryer (1.25 lb), a hand-held video game (0.6 lb), an extra video game (0.25 lb), and a music player (0.4 lb). Using the inequality x ≤ 2.25, can she add all these items to the suitcase? If not, what could be left out to be closest to the maximum weight allowed?

Solution:

Weight of the items

hairdryer = 1.25 lb

hand-held video game = 0.6 lb

an extra video game = 0.25 lb music player = 0.4 lb

The total weight of the items

= 1.25lb + 0.25lb + 0.6lb + 0.4lb

= 2.5 lb.

Total weight - required weight

= 2.5lb - 2.25lb

= 0.25lb

2.5lb is 0.25lb greater than 2.25lb

Therefore, not all items can be added.

She has to leave out an item equivalent to 0.25lb

Item equivalent to 0.25lb is the extra video game

If Li leaves out the extra game, which weighs 0.25 lb, she’d have the maximum weight allowed.

5 0
1 year ago
The function f(x) = x2 has been translated 9 units up and 4 units to the right to form the function g(x). Which represents g(x)?
Alenkinab [10]

For this case, the parent function is given by:

f (x) = x ^ 2

We apply the following transformations:


Vertical translations:

Suppose that k> 0

To graph y = f (x) + k, move the graph of k units upwards:

For k = 9 we have:

h (x) = x ^ 2 + 9


Horizontal translations:

Suppose that h> 0

To graph y = f (x-h), move the graph of h units to the right

For h = 4 we have:

g (x) = (x-4) ^ 2 + 9

Answer:

The function g (x) is given by:

g (x) = (x-4) ^ 2 + 9

7 0
2 years ago
Read 2 more answers
A market research company conducted a survey to find the level of affluence in a city. They defined the category "affluence" for
malfutka [58]

Answer:

A 95% confidence interval for this population proportion is [0.081, 0.159].

Step-by-step explanation:

We are given that a market research company conducted a survey to find the level of affluence in a city.

Out of 267 persons who replied to their survey, 32 are considered affluent.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

                            P.Q.  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of people who are considered affluent = \frac{32}{267} = 0.12

            n = sample of persons = 267

            p = population proportion

<em>Here for constructing a 95% confidence interval we have used One-sample z-test for proportions.</em>

<u>So, 95% confidence interval for the population proportion, p is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                    of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

    = [ 0.12-1.96 \times {\sqrt{\frac{0.12(1-0.12)}{267} } } , 0.12+1.96 \times {\sqrt{\frac{0.12(1-0.12)}{267} } } ]

    = [0.081, 0.159]

Therefore, a 95% confidence interval for this population proportion is [0.081, 0.159].

4 0
2 years ago
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