When you say that two numbers are relatively
prime, it means that both numbers do not have a common factor except 1. Stephen
is incorrect because 38 and 40 are both multiples of 2.
I hope I answered your question. Thank you <span>J</span>
Answer:
56 number of ways
Step-by-step explanation:
This question is a combination question since it involves selection.
Generally, if r objects are to be selected from n pool of objects, this can be done in nCr number of ways.
nCr = n!/(n-r)!r!
If a manager receives 8 applications for a specific position and wants to narrow it down to 5, the number of ways he can do this is 8C5
8C5 = 8!/(8-5)!5!
= 8!/3!5!
= 8*7*6*5!/3*2*5!
= 8*7*6/3*2
= 8*7
= 56 number of ways.
This means that the manager can rank 5 applications in 56 number of ways
In a parallelogram diagonals bisect each other,
=>AT=TX=>4y-2=14=>4y=14+2=>4y =16=>y=16/4=4
And ZT=TY=>2x+12=6x-12
=>12+12=6x-2x
=>24=4x
=>24/4=X
=>6=X
Hope this helps u...!!!
<span>z^3 + 3z^2 -25z - 75 = 0</span>
Factor out common terms in the first two terms, then in the last two terms
<span><span><span><span>z^2</span>(z+3)−25(z+3)=0
</span></span></span>Factor out the common term <span>z+3</span>
<span><span><span>(z+3)(<span>z^2</span>−25)=0
</span></span></span>Ask: When will <span>(z+3)(<span>z^2</span>−25)</span> equal zero?
When <span>z+3=0 </span>or <span><span>z^2</span>−25=0
</span>Solve each of the 2 equations above
<span>z=−3,±5
Hope this helps</span>
