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TEA [102]
2 years ago
10

A statistics instructor who teaches a lecture section of 160 students wants to determine whether students have more difficulty w

ith one-tailed hypothesis tests or with two-tailed hypothesis tests. On the next exam, 80 of the students, chosen at random, get a version of the exam with a 10-point question that requires a one-tailed test. The other 80 students get a question that is identical except that it requires a two-tailed test. The one-tailed students average 7.81 points, and their standard deviation is 1.06 points. The two-tailed students average 7.64 points, and their standard deviation is 1.33 points.
Mathematics
1 answer:
Leona [35]2 years ago
3 0

Answer:

There is no evidence that there is no significant difference between the sample means

Step-by-step explanation:

given that a  statistics instructor who teaches a lecture section of 160 students wants to determine whether students have more difficulty with one-tailed hypothesis tests or with two-tailed hypothesis tests. On the next exam, 80 of the students, chosen at random, get a version of the exam with a 10-point question that requires a one-tailed test. The other 80 students get a question that is identical except that it requires a two-tailed test. The one-tailed students average 7.81 points, and their standard deviation is 1.06 points

The two-tailed students average 7.64 points, and their standard deviation is 1.33 points.

Group   One tailed X     Two tailed Y  

Mean 7.8100 7.6400

SD 1.0600 1.3300

SEM 0.1185 0.1487

N 80       80  

H_0:\bar x=\bar y\\H_a: \bar x \neq \bar y

(Two tailed test)

The mean of One tailed X minus Two tailed Y equals 0.1700

t = 0.8940

 df = 158

p value =0.3727

 p is greater than alpha 0.05

There is no evidence that there is no significant difference between the sample means

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What is the value of x in the equation 4 x plus 8 y equals 40, when y equals 0.8? 4.6 8.4 10 12What is the value of a in the equ
Mama L [17]

Answer:

1. 8.4 2. 15

Step-by-step explanation:

1. 4x+8y= 40

wen y= 0.8

4x+8×0.8=40

4x=40-8×0.8

4x= 40- 6.4= 33.6

....x= 33.6/4 = 8.4

2. 3a+b= 54

wen b= 9

3a+ 9= 54

3a= 54- 9

3a=45

.....a = 45/3 = 15

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8 0
2 years ago
Read 2 more answers
Write an expression that evaluates to true if the int associated with number_of_prizes is divisible (with no remainder) by the i
hodyreva [135]

We need to find the expression for " number_of_prizes is divisible number_of_participants". Also there should not remain any remainder left. On in order words, we can say the reaminder we get after division is 0.

Let us assume number of Prizes are = p and

Number of participants = n.

If we divide number of Prizes by number of participants and there will be not remainder then there would be some quotient remaining and that quotent would be a whole number.

Let us assume that quotent is taken by q.

So, we can setup an expression now.

Let us rephrase the statement .

" Number of Prizes ÷ Number of participants  = quotient".

p ÷ n = q.

In fraction form we can write

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4 0
2 years ago
ryan is making small meat loaves. each small meat loaf uses three fourths pound of meat. how much meat does ryan need to make ei
Tema [17]
You do three fourths times eight and that equals six.
4 0
2 years ago
In the figure below, \overline{AD} AD start overline, A, D, end overline and \overline{BE} BE start overline, B, E, end overline
VLD [36.1K]

Answer:

<u>The measure of the arc CD = 64°</u>

Step-by-step explanation:

It is required to find the measure of the arc CD in degrees.

So, as shown at the graph

BE and AD are are diameters of circle P

And ∠APE is a right angle ⇒ ∠APE = 90°

So, BE⊥AD

And so, ∠BPE = 90° ⇒(1)

But it is given: ∠BPE = (33k-9)° ⇒(2)

From (1) and (2)

∴ 33k - 9 = 90

∴ 33k = 90 + 9 = 99

∴ k = 99/33 = 3

The measure of the arc CD = ∠CPD = 20k + 4

By substitution with k

<u>∴ The measure of the arc CD = 20*3 + 4 = 60 + 4 = 64°</u>

6 0
2 years ago
Use the following compound interest formula to complete the problem.
alexdok [17]

Card P's balance increased by $3.43 more than Card Q's balance. The accumulated total on Card P over the 4 years is $1080.70 and the accumulated total of Card Q is $1,206.28. Based on the principal outlay however, Card P would have netted a higher interest over Card Q when the principal is subtracted from the accumulated value. (For eg. Card P accumulated value $1080.70 less Principal $726.19 equals $354.51).The interests over the 4 years period would be $354.51 and $351.08 respectively, hence Card P having an increase in balance of $3.43 over Card Q.

5 0
2 years ago
Read 2 more answers
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