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VashaNatasha [74]
2 years ago
9

The number of defective bulbs a company produces varies with each batch. Based on the table, which histogram exhibits the skew o

bserved in this data distribution? Batch Size 100-199 200-299 300-399 400-499 500-599 600-699 700-799 Number of Defective Bulbs 5 6 7 6 5 5 5
Mathematics
2 answers:
SSSSS [86.1K]2 years ago
6 0

Answer: Graph 2


Step-by-step explanation:


ra1l [238]2 years ago
4 0

Answer: B) Graph 2

Step-by-step explanation: plato only

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A member of a student team playing an interactive marketing game received the fol- lowing computer output when studying the rela
nirvana33 [79]

Answer:

p_v = 2*P(t_{n-2} > |t_{calc}|)= 0.91

So on this case for the significance level assumed \alpha=0.05 we see that p_v >\alpha so then we can conclude that the result is NOT significant. And we don't have enough evidence to reject the null hypothesis.

So on this case is not appropiate say that :"the more we spend on advertising this product, the fewer units we sell" since the slope for this case is not significant.

Step-by-step explanation:

Let's suppose that we have the following linear model:

y= \beta_o +\beta_1 X

Where Y is the dependent variable and X the independent variable. \beta_0 represent the intercept and \beta_1 the slope.  

In order to estimate the coefficients \beta_0 ,\beta_1 we can use least squares procedure.  

If we are interested in analyze if we have a significant relationship between the dependent and the independent variable we can use the following system of hypothesis:

Null Hypothesis: \beta_1 = 0

Alternative hypothesis: \beta_1 \neq 0

Or in other words we want to check is our slope is significant (X have an effect in the Y variable )

In order to conduct this test we are assuming the following conditions:

a) We have linear relationship between Y and X

b) We have the same probability distribution for the variable Y with the same deviation for each value of the independent variable

c) We assume that the Y values are independent and the distribution of Y is normal  

The significance level assumed on this case is \alpha=0.05

The standard error for the slope is given by this formula:

SE_{\beta_1}=\frac{\sqrt{\frac{\sum (y_i -\hat y_i)^2}{n-2}}}{\sqrt{\sum (X_i -\bar X)^2}}

Th degrees of freedom for a linear regression is given by df=n-2 since we need to estimate the value for the slope and the intercept.  

In order to test the hypothesis the statistic is given by:

t=\frac{\hat \beta_1}{SE_{\beta_1}}

The p value on this case would be given by:

p_v = 2*P(t_{n-2} > |t_{calc}|)= 0.91

So on this case for the significance level assumed \alpha=0.05 we see that p_v >\alpha so then we can conclude that the result is NOT significant. And we don't have enough evidence to reject the null hypothesis.

So on this case is not appropiate say that :"the more we spend on advertising this product, the fewer units we sell" since the slope for this case is not significant.

3 0
2 years ago
Every year the United States Department of Transportation publishes reports on the number of alcohol related and non-alcohol rel
Damm [24]

Complete question:

The line graph relating to the question was not attached. However, the line graph has can be found in the attachment below.

Answer:

17,209

Step-by-step explanation:

The line graph provides information about alcohol-related highway fatalities between year 2001 to 2010.

Determine the average number of alcohol-related fatalities from 2001 to 2006. Round to the nearest whole number.

The average number of alcohol related fatalities between 2001 - 2006 can be calculated thus :

From the graph:

Year - - - - - - - - - - Number of fatalities

2001 - - - - - - - - - - 17401

2002 - - - - - - - - -  17525

2003 - - - - - - - - -  17013

2004 - - - - - - - - - 16694

2005 - - - - - - - - - 16885

2006 - - - - - - - - - 17738

To get the average :

Sum of fatalities / number of years

(17401 + 17525 + 17013 + 16694 + 16885 + 17738) / 6

= 103256 / 6

= 17209.333

Average number of alcohol related fatalities is 17,209 (to the nearest whole number)

6 0
2 years ago
If 2A:3B=5:6 and 3B:2C=36:15 then find A:C​
Aleonysh [2.5K]

Answer:

A: C = 2: 1

Step-by-step explanation:

Please see the attached pictures for the full solution.

Further explanantion (2nd image):

The reason why the ratio of A: C is equal to the ratio if 2A: 2C is that the number of parts of A and C is equal, which is 2 parts. If I were to divide both 2A and 2C by 2 to find the ratio of A: C, I would obtain 15: 15/2. However, ratios are expressed as whole numbers and thus, we would multiply the whole ratio by 2 again and the answer would still be 30: 15. This ratio is not in the simplest form since both can be divided by 15. Thus, dividing both sides of the ratio by 15 will leave us with the final answer of

A: C= 2: 1.

☆ An alternative method is to simplify the ratio 3B: 2C at the beginning.

3B: 2C

= 36: 15

= 12: 5

Multiply the first ratio by 2 so 3B has 12 parts in both ratios:

2A: 3B

= 10: 12

Combining the 2 ratios together,

2A: 3B: 2C

= 10: 6: 5

2A: 2C

= 10: 5

= 2: 1

A: C= 2: 1

6 0
2 years ago
Six years ago, Kelsey opened a savings account that earns 1.2% simple interest every year. She started the account with $600 and
densk [106]

Answer:

600 times .012=7.20

7.20 times 6= 43.20

43.20+ 600= 643.20

the correct answer is b- $643.20

5 0
2 years ago
Read 2 more answers
What is the coefficient of each monomial?<br> a. 5pk<br> b. f<br> c. –9t<br> d. –j
Semenov [28]

Step-by-step explanation:

<em>Look at the picture</em>

a. 5pk → 5

b. f = 1f → 1

c. -9t → -9

d. -j = -1j → -1

5 0
2 years ago
Read 2 more answers
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