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AleksandrR [38]
2 years ago
11

The speed of sound is approximately 340 m / s. How long will it take for the sound to travel from the batter to a spectator who

is seated 30 meters away? How long will it take if the spectator is 150 meters away?
Mathematics
1 answer:
iris [78.8K]2 years ago
4 0
The first answer is 3/34 sec and the second answer is 15/34 sec.

Set up a proportion for these problems.  For the first question,
340/1 = 30/x

Cross multiply:
340*x = 1*30
340x = 30

Divide both sides by 340:
340x/340=30/340
x = 30/340 = 3/34

For the second question,
340/1 = 150/x

Cross multiply:
340*x = 150*1
340x=150

Divide both sides by 340:
340x/340 = 150/340 
x = 150/340 = 15/34
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What single decimal multiplier would you use to decrease by 6% followed by a 19% increase?
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Answer: 13% increase?

Step-by-step explanation: 19-6=13 which means it would be 1.13 the original amount?

7 0
2 years ago
Read 2 more answers
HELP!!
Liono4ka [1.6K]

Answer:

Part 1: The polygon ABCDE reflected across y-axis to get the polygon MNOPQ. So, the polygon ABCDE congruent to polygon MNOPQ.

Part 2: The vertices of polygon VWXYZ are V(1, 3), W(-1, 7), X(-7, 7), Y(-5, 3), and Z(-3, 1).

Step-by-step explanation:

Part 1:

The vertices of the polygon ABCDE are A(2, 8), B(4, 12), C(10, 12), D(8, 8), and E(6, 6).

The vertices of the polygon MNOPQ are M(-2, 8), N(-4, 12), O(-10, 12), P(-8, 8), and Q(-6, 6).

We need to find the transformation or sequence of transformations that can be performed on polygon ABCDE to show that it is congruent to polygon MNOPQ.

The relation between the vertices of ABCDE and MNOPQ are defined as

(x,y)\rightarrow (-x,y)

It means the polygon ABCDE reflected across y-axis to get the polygon MNOPQ. So, the polygon ABCDE congruent to polygon MNOPQ.

Part 2:

If polygon MNOPQ is translated 3 units right and 5 units down, then

(x,y)\rightarrow (x+3,y-5)

M(-2,8)\rightarrow V(-2+3,8-5)=V(1,3)

N(-4,12)\rightarrow W(-4+3,12-5)=W(-1,7)

O(-10,12)\rightarrow X(-10+3,12-5)=X(-7,7)

P(-8,8)\rightarrow Y(-8+3,8-5)=Y(-5,3)

Q(-6,6)\rightarrow Z(-6+3,6-5)=Z(-3,1)

Therefore the vertices of polygon VWXYZ are V(1, 3), W(-1, 7), X(-7, 7), Y(-5, 3), and Z(-3, 1).

6 0
1 year ago
1. If Ray ran 10.5 miles in 7 days, how many miles
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1 year ago
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Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th
Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

(a)

The bid should be greater than $10,000 to get accepted by the seller. Let bid x be a continuous random variable that is uniformly distributed between

$10,000 and $15,000

The interval of the accepted bidding is [ {\rm{\$ 10,000 , \$ 15,000}], where b = $15000 and a = $10000.

The interval of the provided bidding is [$10,000,$12,000]. The probability is calculated as,

\begin{array}{c}\\P\left( {X{\rm{ < 12,000}}} \right){\rm{ = }}1 - P\left( {X > 12000} \right)\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{12000}^{15000}\\\end{array}

=1- \frac{[15000-12000]}{5000}\\\\=1-0.6\\\\=0.4

(b)  The interval of the accepted bidding is [$10,000,$15,000], where b = $15,000 and a =$10,000. The interval of the given bidding is [$10,000,$14,000].

\begin{array}{c}\\P\left( {X{\rm{ < 14,000}}} \right){\rm{ = }}1 - P\left( {X > 14000} \right)\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{14000}^{15000}\\\end{array} P(X14000)

=1- \frac{[15000-14000]}{5000}\\\\=1-0.2\\\\=0.8

(c)

The amount that the customer bid to maximize the probability that the customer is getting the property is calculated as,  

The interval of the accepted bidding is [$10,000,$15,000],

where b = $15,000 and a = $10,000. The interval of the given bidding is [$10,000,$15,000].

\begin{array}{c}\\f\left( {X = {\rm{15,000}}} \right){\rm{ = }}\frac{{{\rm{15000}} - {\rm{10000}}}}{{{\rm{15000}} - {\rm{10000}}}}\\\\{\rm{ = }}\frac{{{\rm{5000}}}}{{{\rm{5000}}}}\\\\{\rm{ = 1}}\\\end{array}

(d)  The amount that the customer bid to maximize the probability that the customer is getting the property is $15,000, set by the seller. Another customer is willing to buy the property at $16,000.The bidding less than $16,000 getting considered as the minimum amount to get the property is $10,000.

The bidding amount less than $16,000 considered by the customers as the minimum amount to get the property is $10,000, and greater than $16,000 will depend on how useful the property is for the customer.

5 0
2 years ago
-10√v-10=-60 Show All Steps.
docker41 [41]
-10rt(v-10)=-60
(-10rt(v-10))/-10=-60/-10
rt(v-10)=6
(v-10)^2=6^2
v-10=36
v-10+10=36+10
v=46
5 0
1 year ago
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