Answer:
You have to multiply the denorminator to both sides in order to make x the subject :


I wanna say (C) would be your best bet correct me if I’m wrong
Ur answer is 6 (20+20+20+20+20+20+21+21+21+21+21+21+21+21+21+21+21+21=372) and they need at least 362 hope this helps I'm pretty sure this is right sorry if it's wrong but it seems right to me
To solve this problem, we must first convert all of the numbers represented by words into their numeral equivalents so we can simplify. To do this, we must remember that the ones place is the first to the left of the decimal point, and the tens place is one place farther to the left. If we have 4 tens and 3 ones, this is the same as 43 (we put the digit 4 in the tens place and the digit 3 in the ones place). If we replace our words with our new numerical value, we get:
43 * 10
To solve this, we just multiply these two numbers together, which gives us:
430
Therefore, your answer is 430.
Hope this helps!
Answer: 985 g
Step-by-step explanation:
Total mass = 8 × 500g = 4000g
Let the three new packs be X, Y, and Z, for first, second, and third pack respectively.
4000g = X + Y + Z
let's put X and Z in terms of Y, since we're trying to solve for the second pack.
X = 2Y, and Z = Y + 60
Therefore,
4000 = X + Y + Z
4000 = 2Y + Y +Y + 60
4000 = 4Y +60
4000 - 60 = 4Y
3940 = 4Y
3940 ÷ 4 = Y
985g = Y = mass of the second pack