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marshall27 [118]
2 years ago
7

If a box of clothes weighing 10 lbs (4.5 kg) and a box of books weighing 10 lbs (4.5 kg) were placed on a scale, what is most li

kely to occur?
Mathematics
2 answers:
galina1969 [7]2 years ago
8 0

Answer:

9 kg

Step-by-step explanation:

Given that if a box of clothes weighing 10 lbs (4.5 kg) and a box of books weighing 10lbs.

It is most likely to balance if they are placed on different scales.

If it is placed on the same scale it will show 9 kg.

Hence answer is 9 kg.

sveta [45]2 years ago
7 0
The scale will read 8 kgs
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S = d/t

st = d

t = d/s

The time going is t1.
The time returning is t2.
The total time is 4 hours, so we have t1 + t2 = 4

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t1 = 16/(9 + c)

t2 = 16/(9 - c)

t1 + t2 = 16/(9 + c) + 16/(9 - c)

4 = 16/(9 - c) + 16/(9 + c)

1 = 4/(9 - c) + 4/(9 + c)

(9 + c)(9 - c) = 4(9 - c) + 4(9 + c)

81 - c^2 = 36 - 4c + 36 + 4c

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c + 3 = 0   or   c - 3 = 0

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Step-by-step explanation:

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A helicopter flies 8 km due north from A to B. It then flies 5 km from B to C and returns to A as shown in the figure. Angle ABC
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Please consider the attached graph.

We have been given that a helicopter flies 8 km due north from A to B. It then flies 5 km from B to C and returns to A as shown in the figure. The measure of angle ABC is 150°. We are asked to find the area of triangle ABC.

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An insurance company collected data from a class of high school sophomores on whether or not they have a cell phone and whether
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Answer:

C. Those who have a car tend to have a cell phone.

Step-by-step explanation:

The relative frequency for a data set n is calculated by dividing each frequency x_i by n.

We have a table that relates the use of cars and cell phones.

First, we take from the table the population that has a car.

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Then we calculate the relative frequencies f_{x_i} for those who have a cell phone and those who do not.

______________________________________________

Relative frequency   Students with car  n = 18.

-------------------------------------------------- --------------------------------------

C<em>ell phone     No cell phone      Total n</em>

 12/18                    6/18                     18

_______________________________________________

_______________________________________________

Relative frequency   Students with car  n = 18.

-------------------------------------------------- --------------------------------------

C<em>ell phone     No cell phone      Total n</em>

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________________________________________________

Most students who have a car also have a cell phone.

Now we calculate the relative frequency for students who do not have a car.

_______________________________________________

Relative frequency  Students without a car  n = 7

-------------------------------------------------- --------------------------------------

<em>Cell phone       No cell phone             Total  n</em>

 2/7                     5/7                          7

_______________________________________________  

_______________________________________________

Relative frequency  Students without a car  n = 7

-------------------------------------------------- --------------------------------------

<em>Cell phone</em>      <em>  No</em> <em>cell phone           Total  n</em>

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_______________________________________________

Most students who do not have a car do not have a cell phone either.

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