Which statements are true about the reflectional symmetry of a regular heptagon? Check all that apply. It has only 1 line of ref
2 answers:
The answer is:
1- A line of symmetry will connect a vertex and a midpoint of an opposite side.
2- It has -fold symmetry.
The explanation for this answer is shown below:
1- By definition, a line of symmetry is an imaginary line that divides a figure into two equal images or equal halves. If you connect a vertex and a midpoint of an opposite side of an heptagon by drawing a line, you will obtain two equal halves.
2- An heptagon has seven vertices, therefore, based on the information mentioned above, it has -fold symmetry.
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Answer:
She will pay $7,500 interest over the 5 years
She will have to pay back $17,500 in total
Step-by-step explanation:
Let us revise the rule of the simple interest
<em>I</em> = <em>Prt</em> and <em>A</em> = <em>P</em>(1 +<em> rt</em>) , where:
- A = Total Accrued Amount (principal + interest)
- P = Principal Amount
- I = Interest Amount
- r = Rate of Interest per year in decimal
- t = Time Period involved in months or years
∵ Leah borrows £10,000 over 5 years at a simple interest rate of 15%.
∴ P = 10,000
∴ t = 5
∴ r = 15% = = 0.15
→ Substitute them in the first rule to find the interest
∵ I = 10,000(0.15)(5)
∴ I = 7,500
∴ She will pay $7,500 interest over the 5 years
→ Let us find A
∵ A = 10,000(1 + 0.15×5)
∴ A = 17,500
∴ She will have to pay back $17,500 in total
The first step for finding out if the expression provided is equivalent to 
is to reduce the fraction with
.
Now reduce the fraction with y.
Finally,, reduce the fraction with 8 to get your final answer.
Let me know if you have any further questions.
:)
Now reduce the fraction with y.
Finally,, reduce the fraction with 8 to get your final answer.
Let me know if you have any further questions.
:)
Answer:
Elements are of the form
(i)
(ii)
(iii)
(iv)
(v) (a,b) where a>b=
(vi) [a,b] where a>b=
Step-by-step explanation:
Given intervals are,
(i) [a,a] (ii) [a,a) (iii) (a,a] (iv) (a,a) (v) (a,b) where a>b (vi) [a,b] where a>b.
To show all its elements,
(i) [a,a]
Imply the set including aa from left as well as right side.
Its elements are of the form.
Since there is a singleton element a of real numbers, this set is empty.
Because there is no increment so if then the set [a,a] represents singleton sets, and singleton sets are empty so is [a,a].
(ii) [a,a)
This means given interval containing a by left and exclude a by right.
Its elements are of the form.
Since there is a singleton element a of real numbers withis the set, this set is empty.
Because there is no increment so if then the set [a,a) represents singleton sets, and singleton sets are empty so is [a.a).
(iii) (a,a]
It means the interval not taking a by left and include a by right.
Its elements are of the form.
Since there is a singleton element a of real numbers, this set is empty.
Because there is no increment so if then the set (a,a] represents singleton sets, and singleton sets are empty so is (a,a].
(iv) (a,a)
Means given set excluding a by left as well as right.
Since there is a singleton element a of real numbers, this set is empty.
Its elements are of the form.
Because there is no increment so if then the set (a,a) represents singleton sets, and singleton sets are empty, so is (a,a).
(v) (a,b) where a>b.
Which indicate the interval containing a, b such that increment of x is always greater than increment of y which not take x and y by any side of the interval.
That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,
e.t.c
So this set is connected and we know singletons are connected in . Hence given set is empty.
(vi) [a,b] where .
Which indicate the interval containing a, b such that increment of x is always greater than increment of y which include both x and y.
That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,
e.t.c
So this set is connected and we know singletons are connected in . Hence given set is empty.