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Marat540 [252]
2 years ago
5

You work at a photography store. A customer has a picture that is 4.5 inches tall. The customer wants a reduced copy of the pict

ure to fit a space of 1.8 inches tall on a postcard. What scale factor should you use to reduce the picture to the correct size?
Mathematics
2 answers:
Luda [366]2 years ago
6 0
To determine the scale factor that should be used in order to correct the size of the post card, we simply have to divide the original length of the picture which is 4.5 inches by the space available, 1.8 inches. This gives an answer of,
                           scale factor = 4.5 inches / 1.8 inches = 2.5
garik1379 [7]2 years ago
3 0

Answer:

0.4

Step-by-step explanation:

The scale factor is the ratio of the lenght of a figure compared to the lenght of another figure and it can be used to enlarge or reduce a shape. In this case, as the customer wants to reduce the picture, to calculate the scale factor you have to divide the small length by the big length.

Scale Factor Reduction= Small length /Big length= 1.8/4.5= 0.4

The scale factor is 0.4.

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Answer: visit the US Bureau of Labor Statistics website to find information on both careers

The career section

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Step-by-step explanation: there is none

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2 years ago
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If ce = 7x+4, find the value of x
Alex787 [66]

Hey there,

To find the value of x we can take the two, CD or DE and set them equal to CE.

First step is set the lines equal to each other:

  • x + 3 + 8x - 9 = 7x + 4

Now we combine like terms:

  • 9x - 6 = 7x + 4

Then we subtract 7x from both sides:

  • 2x - 6 = 4

Add 6 to both sides:

  • 2x = 10

Lastly we divide both sides by 2:

  • x = 5

So the value of x would have to be 5.  

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2 years ago
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A woman sold an article for 200 Ghana cedis and made a profit of 25%. Find the cost price of the article​
marta [7]

Answer:

160

Step-by-step explanation:

4 0
2 years ago
Stan made 24 sales in 6 hours . what is the ratio of sales to hours?
Furkat [3]
Let s = sale

Let h = hours

The ratio is s to h, which can be written as a fraction as 24/6.
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A nationwide sample of influential Republicans and Democrats was asked as a part of a comprehensive survey whether they favored
pickupchik [31]

Answer:

We conclude that there is an equal or larger proportion of Republicans in favor of lowering the standards.

Step-by-step explanation:

<u>The complete question is</u>: A nationwide sample of influential Republicans and Democrats was asked as a part of a comprehensive survey whether they favored lowering environmental standards so that high-sulfur coal could be burned in coal-fired power plants. The results were:

Number sampled: 1,000 (republican) , 800 (democrats)

Number in favor: 200 (republican) , 168 (democrats)

At the 0.02 level of significance, can we conclude that there is a larger proportion of Democrats in favor of lowering the standards? Determine the p-value.

Let p_1 = <u><em>proportion of Republicans in favor of lowering the standards</em></u>.

p_2 = <u><em>proportion of Democrats in favor of lowering the standards</em></u>.

SO, Null Hypothesis, H_0 : p_1 \geq p_2     {means that there is an equal or larger proportion of Republicans in favor of lowering the standards}

Alternate Hypothesis, H_A : p_1 < p_2     {means that there is a larger proportion of Democrats in favor of lowering the standards}

The test statistics that would be used here <u>Two-sample z-test for</u> <u>proportions</u>;

                         T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~ N(0,1)

where, \hat p_1 = sample proportion of Republicans in favor of lowering the standards = \frac{200}{1000} = 0.20

\hat p_2 = sample proportion of Democrats in favor of lowering the standards = \frac{168}{800} = 0.21

n_1 = sample of Republicans = 1000

n_2 = sample of Democrats = 800

So, <u><em>the test statistics</em></u>  =  \frac{(0.20-0.21)-(0)}{\sqrt{\frac{0.20(1-0.20)}{1000}+\frac{0.21(1-0.21)}{800} } }

                                     =  -0.52

The value of z test statistics is -0.52.

<u>Now, P-value of the test statistics is given by the following formula; </u>

            P-value = P(Z < -0.52) = 1 - P(Z \leq 0.52)

                          = 1 - 0.6985 = 0.3015

Now, at 0.02 significance level, the z table gives a critical value of -2.054 for left-tailed test.

Since our test statistic is more than the critical value of z as -0.52 > -2.054, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <em><u>we fail to reject our null hypothesis</u></em>.

Therefore, we conclude that there is an equal or larger proportion of Republicans in favor of lowering the standards.

7 0
2 years ago
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