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2 years ago

10

Suppose you invest $1600 at an annual interest rate of 4.6% compounded continuously. Using the formula A(t) =P*e^rt , how much w

ill you have in the account after 4 years

1 answer:

artcher [175]2 years ago

8 0

Just fill in the given data and evaluate the expression:

A = $1600*e^(0.046*4) = $1923.23 (rounded up to the nearest cent)

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A factory received a shipment of 38 sprockets, and the vendor who sold the items knows there are 5 sprockets in the shipment tha

weeeeeb [17]

Answer:

a) 0.00019923%

b) 47.28%

Step-by-step explanation:

a) To find the probability of all sockets in the sample being defective, we can do the following:

The first socket will be in a group where 5 of the 38 sockets are defective, so the probability is 5/38

The second socket will be in a group where 4 of the 37 sockets are defective, as the first one picked is already defective, so the probability is 4/37

Expanding this, we have that the probability of having all 5 sockets defective is: (5/38)*(4/37)*(3/36)*(2/35)*(1/34) = 0.0000019923 = 0.00019923%

b) Following the same logic of (a), the first socket have a chance of 33/38 of not being defective, as we will pick it from a group where 33 of the 38 sockets are not defective. The second socket will have a chance of 32/37, and so on.

The probability will be (33/38)*(32/37)*(31/36)*(30/35)*(29/34) = 0.4728 = 47.28%

5 0

2 years ago

Easton is working two summer jobs, making $18 per hour tutoring and $9 per hour clearing tables. Last week Easton worked 4 times

Mama L [17]

Answer:

the new Zealand international was the first time he had scored in a day and a half century for any of his

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2 years ago

11) The Cost of maintaing a

dezoksy [38]

Answer:

a). Cost of 44 pupils = $14265

b). Least number of pupils = 31

Step-by-step explanation:

The given question is incomplete; here is the complete question.

The cost of maintaining a school is partly constant and partly varies as the number of pupils. With 50 pupils, the cost is $15,705.00 and with 40 pupils, it is $13,305.00.

(a) Find the cost when there are 44 pupils.

(b) If the fee per pupil is $360.00, what is the least number of pupils for which the school can run without a loss?

Let the equation representing the total cost of maintaining a school is,

C = ax + b

Where C = Total cost of maintaining a school

a = Fee per pupil

b = Fixed running cost

x = number of pupils

a). Cost of 50 pupils = $15705

Equation will be,

15705 = 50a + b -------(1)

Cost of 40 pupils = $13305

Equation will be,

13305 = 40a + b --------(2)

By subtracting equation (2) from equation (1),

15705 - 13305 = (50a + b) - (40a + b)

2400 = 10a

a = 240

From equation (1),

b = 3705

Equation representing the total cost will be,

C = 240x + 3705

If x = 44

C = 240(44) + 3705

C = $14265

b). If the fee per pupil 'a' = $360

Let the number of pupils = p

Total fee of 'p' pupils = $360p

Total cost to run the school will be = 3705 + 240p

For the school not to be in the loss,

360p ≥ 3705 + 240p

360p - 240p ≥ 3705

120p ≥ 3705

p ≥ $\frac{3705}{120}$

p ≥ 30.875

Therefore, to run the school without loss, number pupils should be at least 31.

3 0

2 years ago

Anja is creating a triangle using three straws. The two shorter straws have lengths of 20 cm and 21 cm. How long, in centimeters

Digiron [165]

A^2 + b^2 = c^2...a and b are the legs and c is the hypotenuse
20^2 + 21^2 = c^2
400 + 441 = c^2
841 = c^2
sqrt 841 = c
29 = c <== third straw will be 29 cm

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2 years ago

Draw a double number line to show that 6 out of 25 M&Ms are green then use it to find what percent are green

Talja [164]

Answer:

Egg

Step-by-step explanation:

eggeggeggeggeggeggeggeggeggeggeggeggeggeggeggeggeggeggeggegg

4 0

2 years ago