Question

A triangle has vertices at B(−3, 0), C(2, −1), D(−1, 2). Which transformation would produce an image with vertices B″(−2, 1), C″(3, 2), D″(0, −1)?
(x, y) → (x, −y), (x, y) → (x + 1, y + 1)
(x, y) → (−x, y), (x, y) → (x + 1, y + 1)
(x, y) → (x, −y), (x, y) → (x + 2, y + 2)
(x, y) → (−x, y), (x, y) → (x + 2, y + 2)

Answer 1

Answer:

A. (x, y) → (x,-y), (x, y) → (x + 1, y + 1)

Step-by-step explanation:

Plot points B, C and D on the coordinate plane (blue points in attached diagram).

1 transformation is reflection across the x-axis with the rule

(x,y)→(x,-y)

and it maps these points to

• B(-3,0)→B'(-3,0)
• C(2,-1)→C'(2,1)
• D(-1,2)→D'(-1,-2)

These image points are marked in green in attached diagram.

2 transformation is translation 1 unit to the right and 1 unit up with the rule

(x,y)→(x+1,y+1)

and it maps previous image points to

• B'(-3,0)→B''(-2,1)
• C'(2,1)→C''(3,2)
• D'(-1,-2)→D''(0,-1)

Answer 2

Answer:

actually A is wrong because I was on FLVS and it was wrong on there.

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