Would it be y = 18t + 18r?
To find the dimensions you can just factor the equation...
x^2+4x-21
x^2-3x+7x-21
x(x-3)+7(x-3)
(x+7)(x-3) and this is equal to LW or WL
And note that x>3 for any possible solution.
Answer:
The answer is "Screen B is wider , because 5.3 is greater than 5 and one-third".
Step-by-step explanation:
The mobile display unit must be made similar. Phone A uses a decimal device, and telephone B uses a fraction in this case.
It's easier for you to use. Attempt using the decimal. The width of the phone B fraction could then be translated to decimal width. The computing is:
= 5 cm +
cm
= 5 cm + 0.333cm
= 5.333 cm
It is evident from here that the wider screen of Phone B is than that of Phone A.
49.50 because you take 35 plus 20 which equals 55, then subtract 10% and you get 49.5 so I then added a zero and got 49.50