A. The number of 10-boards Peter bought is equal to n divided by 10. Then, each of the 10-boxes will get two boxes of nails. The number of boxes of nails that Peter will have after buying n boards will be,
N = (2)(n/10)
Simplifying,
<em> N = n/5</em>
b. If the number of boards are 90 then,
N2 = (90/10)(2)(100 nails/box)
N2 = 1800
Answer: 1800
Answer:
I hope this image and explanation helps you!
Step-by-step explanation:
All students in the eighth grade were surveyed, so we can make the valid conclusion that 18% of all students in the eighth grade at Lincoln Junior High School have pancakes as their favorite breakfast.
However, the question did not ask about the students' favorite meal of the day, so we cannot draw any valid conclusions about the students' favorite meal.
The valid conclusion:
18% of all students in the eighth grade at Lincoln Junior High School have pancakes as their favorite breakfast, but we cannot conclude anything about the percent of the population who have breakfast as their favorite meal.
85 x 0.07 = 5.95
Total = 85 + 5.95 = 90.95%
Most likely, polygon <span>ABCD</span> has sides of known lengths.
It is also likely that one of the sides of polygon <span>EFGH</span> (not <span>EH</span>) is also known. For instance, its side <span>EF</span>.
If the above is true, we can find the scaling factor as a ratio between lengths of corresponding sides:
<span>r=<span><span>EF</span><span>AB</span></span></span>
Since this ratio is constant for any two corresponding lengths,
<span>r=<span><span>EH</span><span>AD</span></span></span>
From the last two equations we can derive:
<span>EH=AD⋅<span><span>EF</span><span>AB</span></span></span>
Hope That Helped : ) (Took a minute)
Ho ho ho, lets get this party started
ok so I'm just really excited to use this stuff that I just learned
so
multiplicites
if a root or zero has an even multilicity, the graph bounces on that root
if the root or zero has an odd multiplicty, the graph goes through that root
so
roots are
-1
2
4
multiplicty is how many times it repeats
2 has even multiplity
we just do 2 is odd and 1 is even so
for roots, r1 and r2, the facotrs would be
(x-r1)(x-r2)
so
(x-(-1))^1(x-2)^2(x-4)
(x+1)(x-2)^2(x-4)
this is a 4th degre equaton
normally, it is goig from top right to top left
it is upside down
theefor it has negative leading coefient
y=-k(x+1)(x-4)(x-2)^2
