Answer: 8.1%
Step-by-step explanation:
Given : 

Let x be the random variable that represents the actual speeds of cars.
The speed limit on a road is 60 mph.
Using formula ,
, we have for x= 60+10=70

Using z-table for right-tailed test value, The probability of cars exceed the speed limit by more than 10 mph will be

Hence, the percentage of cars exceed the speed limit by more than 10 mph is 8.1%.
Answer:
Option d)

Step-by-step explanation:
We are given the following in the question:
Three of four people believed that the state of the economy was the country's most significant concern.
They would like to test the new data against this prior belief.
The null hypothesis will state that the three of four people believed that the state of the economy was the country's most significant concern.
The alternate hypothesis will state that this is not true. It states that people believed that the state of the economy was the country's most significant concern is not the same.

We design the null and the alternate hypothesis

Answer:
Yes, but it is not linear. It is exponential : 
Step-by-step explanation:
On the first day we have 5 bacteria.
On the second day we will have 5*2 = 10 bacteria.
On the third day we will have 10*2 = 5*2*2 = 5*2^2 = 20 bacteria.
On the fourth day we will have 20*2 = 5*2*2*2 = 5*2^3 = 40 bacteria.
We can see that
,
where x is a number of days and f(x) gives us the number of bacteria.
N - Nicholes money
M - Marys money
(1) N + M = 4800 ⇒ N = 4800 - M
(2) N - 800 = M - 2/5M ⇒ N - 800 = 3/5M
subtitute (1) to (2)
4800 - M - 800 = 3/5M
4000 - M = 3/5M
-M - 3/5M = -4000
-8/5M = -4000 |multiply both sides by (-5/8)
M = 2500
subtitute the value of M to (1)
N = 4800 - 2500
N = 2300
Answer: Mary had at first $2500. (Nichole: $2300).
Answer:
The mean is the better method.
Step-by-step explanation:
The best way to meassure the average height is throught mean. The mean of a sample is the average of that sample's height, and it will be a good estimate for the population's average height.
The mode just finds the most frequent height. Even tough the most frequent height will influence the average height, knowing only what height is the most frequent one doesnt give you enough informtation about how the height is centrally distributed.
As for the median, it is fine to use the median of a sample to estimate the median of the population, but if you use the median to estimate the average height you may have a few issues. For example, if you include babies in your population, the babies will push the average height down a lot and they are far below te median height. This, as a result, will give you a median height of a sample way above the average height of the population, becuase median just weights every person's height the same, while average will weight extreme values more, in the sense that a small proportion of extreme values can push the average far from the median.