Question

Which point is an x-intercept of the quadratic function f(x)=(x-8)(x-9)?

Answer 1

The zeroes are (0,8) and (0,9)

Use the zero product property to find this
(x-8)=0
x=8

(x-9)=0
x=9

Answer 2

Answer:

The points are (8,0) and (9, 0)

Step-by-step explanation:

Given the function

$f(x)=(x-8)(x-9)$

we have to find the point which is an x-intercept of the quadratic function.

X-intercept is the x-coordinate of a point where a graph of function intersects the x-axis i.e the value of x at which the value of y is 0.

Hence, to find x-intercept we have to put the value of y=0 in f(x)

$(x-8)(x-9)=0$

Using zero product property

⇒ $(x-8)=0\text{ or }(x-9)=0$

$x=8\text{ or }x=9$

The points are (8,0) and (9, 0)