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stich3 [128]
1 year ago
5

Jill is standing at the base of her apartment building. She measures the angle of elevation to the top of a nearby tower to be 4

0º. Then Jill goes to the roof of her apartment building, directly above her previous position, and measures the angle of elevation to the top of the same tower to be 30°. If the height of the tower is 100 meters, the height of Jill's apartment building is
Mathematics
2 answers:
almond37 [142]1 year ago
4 0
1) From the measure of 40°, you can write:

tan(40°) = 100/x, where x is the base from the building to the tower

⇒x=100/tan(40°) = 119,18 m

2) From the measure of 30°, you can write

tan(30°) = y / 119,18, where y is the height from the roof of Jill's building to the top of the tower.

Then, y = tan(30°) * 119,18 = 68,81 m

3) The height of Jill's building is 100 - 68,81 = 31,19 m
tankabanditka [31]1 year ago
4 0

Answer:

Its 31.2

Step-by-step explanation:

@Edufirst Check Your Work ("," ".")

x = 100/tan 40 = 100/0.8391 = 119.18 meters

y = 119.18 x tan 30 = 68.8 meters

100 - 68.8 = 31.2 meters

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A statistics instructor who teaches a lecture section of 160 students wants to determine whether students have more difficulty w
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Answer:

There is no evidence that there is no significant difference between the sample means

Step-by-step explanation:

given that a  statistics instructor who teaches a lecture section of 160 students wants to determine whether students have more difficulty with one-tailed hypothesis tests or with two-tailed hypothesis tests. On the next exam, 80 of the students, chosen at random, get a version of the exam with a 10-point question that requires a one-tailed test. The other 80 students get a question that is identical except that it requires a two-tailed test. The one-tailed students average 7.81 points, and their standard deviation is 1.06 points

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N 80       80  

H_0:\bar x=\bar y\\H_a: \bar x \neq \bar y

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3 0
2 years ago
5.
andrew-mc [135]

Answer:

The  angle of depression from Platform A to Platform B is 43.1^{\circ}

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Refer the attached figure

The horizontal distance between the  platforms is 500 feet i.e. BC = 500

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We are supposed to find the  angle of depression from Platform A to Platform B

Hypotenuse = 685

Base = 500

Cos \theta = \frac{Base}{Hypotenuse}\\Cos \theta = \frac{500}{685}\\\theta = cos^{-1}(\frac{500}{685})\\\theta = 43.11^{\circ}

Hence  the  angle of depression from Platform A to Platform B is 43.1^{\circ}

4 0
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