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stich3 [128]
2 years ago
5

Jill is standing at the base of her apartment building. She measures the angle of elevation to the top of a nearby tower to be 4

0º. Then Jill goes to the roof of her apartment building, directly above her previous position, and measures the angle of elevation to the top of the same tower to be 30°. If the height of the tower is 100 meters, the height of Jill's apartment building is
Mathematics
2 answers:
almond37 [142]2 years ago
4 0
1) From the measure of 40°, you can write:

tan(40°) = 100/x, where x is the base from the building to the tower

⇒x=100/tan(40°) = 119,18 m

2) From the measure of 30°, you can write

tan(30°) = y / 119,18, where y is the height from the roof of Jill's building to the top of the tower.

Then, y = tan(30°) * 119,18 = 68,81 m

3) The height of Jill's building is 100 - 68,81 = 31,19 m
tankabanditka [31]2 years ago
4 0

Answer:

Its 31.2

Step-by-step explanation:

@Edufirst Check Your Work ("," ".")

x = 100/tan 40 = 100/0.8391 = 119.18 meters

y = 119.18 x tan 30 = 68.8 meters

100 - 68.8 = 31.2 meters

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Gianna is going to throw a ball from the top floor of her middle school. When she throws the ball from 32feet above the ground,
Jlenok [28]

Answer:

There are two times for the ball to reach a height of 64 feet:

1 second after thrown ⇒ the ball moves upward

2 seconds after thrown ⇒ the ball moves downward

Step-by-step explanation:

* Lets explain the function to solve the problem

- h(t) models the height of the ball above the ground as a function

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- To find the time when the height of the ball is above the ground

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∵ h = 64

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∴ t² - 3t + 2 = 0 ⇒ factorize it

∴ (t - 2)(t - 1) = 0

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∴ t = 2

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- That means the ball will be at height 64 feet after 1 second when it

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* There are two times for the ball to reach a height of 64 feet

  1 second after thrown ⇒ the ball moves upward

  2 seconds after thrown ⇒ the ball moves downward

3 0
2 years ago
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