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kiruha [24]
2 years ago
5

Given the function f(x) = 3x, find the value of f−1(81).

Mathematics
1 answer:
Shalnov [3]2 years ago
4 0
Given the function f (x) = 3x, find the value of f-1 (81).
 For this case, the first thing you should do is rewrite the function.
 We have then:
 y = 3 ^ x
 From here, we clear the value of x:
 log3 (y) = log3 (3 ^ x)
 log3 (y) = x
 Then, we rewrite the function again:
 f (x) ^ - 1 = log3 (x)
 Now, we evaluate the inverse function for x = 81:
 f (81) ^ - 1 = log3 (81)
 f (x) ^ - 1 = 4
 Answer:
 the value of f-1 (81) is: 
 f (x) ^ - 1 = 4
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Step-by-step explanation:

(7x+4)(7x+4)=(7x+4)^2 ( using (a+b)(a+b)=(a+b)^2 )

=(7x)^2+2(7x)(4)+4^2 ( using (a+b)^2=a^2+2ab+b^2 )

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Option B) (7x+4)(7x+4) is correct

The product result in a perfect square trinomial is

(7x+4)(7x+4)=49x^2+56x+14

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