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Annette [7]
2 years ago
11

Mabel is comparing the prices of two car rental companies. Company A charges $35 per day and an additional $15 as service charge

s. Company B charges $42 per day and an additional $10 as service charges.Part A: Write an equation to represent each company's total charges for renting a car for a certain number of days. For both equations (one for Company A and one for Company
b., define the variable used.Part B: Which company would charge less for renting a car for 6 days? Justify your answer. Part C: How much money is saved by using the services of Company A instead of Company B to rent a car for 10 days?

Mathematics
1 answer:
tester [92]2 years ago
4 0
I hope that helps you out

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Select the correct answer. Sarah wants to print copies of her artwork. At the local print shop, it costs her $1 to make 5 copies
Ber [7]

$1 = 5copies means

$5 = 25 copies obviously

then

$x = 100 copies

100 / 5 = $x

so she needs

$20

3 0
2 years ago
Read 2 more answers
According to the journal Chemical Engineering, an important property of a fiber is its water absorbency. A random sample of 20 p
Feliz [49]

Answer:

Step-by-step explanation:

a )

sample mean = sum total of given data / no of data

= 415.35 / 20 = 20.76

To calculate the median we arrange the data in ascending order and take the average of 10 th and 11 th term .

= 20.50 + 20.72 / 2

= 20.61

b ) To calculate the 10% trimmed mean , we neglect the largest 10% and smallest 10 % data and then calculate the mean . Here we neglect the first two smallest and last two greatest

(18.92 + 19.25 ..... + 22.43 + 22.85) / 16

= 20.74

c )

We can easily plot the data on number line from 17 to 24

d )

Maximum value of data set = 23.71 and minimum value is 18.04

mean is 20.76 , median is 20.61 and trimmed mean is 20.74

They are between maximum and minimum values of given data . Hence there is no outliers .

4 0
2 years ago
Angle KLM and angle MLN are a linear pair. Ray LR is to be added to the diagram so that it is opposite ray LM. Which is true abo
lesya [120]
Angles RLN and MLK would be vertical angles.
Right. Vertical angles are formed when their sides share the same lines. RL shares the same line with LM and NL shares the same line with LK (see the attached diagram), so that means both angles form a vertical pair.

Angles RLN and MLN would be vertical angles.
Wrong.
They are linear pairs, because they are adjacent and supplementary. Adjacent angles share a side – in this case, LN. Supplementary angles sum 180°, which you can see is right because the other sides (ML and RL) are in the same line. RLN and MLN sum the same as the size of RLM, which is a line, so it’s 180°.  <span>

Angles RLN and KLM would be a linear pair. </span>
Wrong.
They would be a vertical pair (see definition of vertical pair in the first option). RL is opposed to LM and LN is opposed to KL.

Angles RLN and KLN would be a linear pair.
Wrong.
KLN is actually a line, so it’s actually 180°, so it can’t be a linear pair with KLN. Linear pairs sum 180°, which is impossible because KLN itself is already 180°, so any sum will throw a higher number.



9 0
2 years ago
Read 2 more answers
The two-way table shows the number of sport utility vehicles with certain features for sale at the car lot.
irinina [24]
A randomly selected car with no 4 wheel drive....so there are 40 cars with no 4 wheel drive

cars with 3rd row seats...that do not have 4 wheel drive...there are 12

so the probability is : 12/40 = 0.3 <==
5 0
2 years ago
Read 2 more answers
let x = the amoun of raw sugar in tons a procesing plant is a sugar refinery process in one day . suppose x can be model as expo
anygoal [31]

Answer:

The answer is below

Step-by-step explanation:

A sugar refinery has three processing plants, all receiving raw sugar in bulk. The amount of raw sugar (in tons) that one plant can process in one day can be modelled using an exponential distribution with mean of 4 tons for each of three plants. If each plant operates independently,a.Find the probability that any given plant processes more than 5 tons of raw sugar on a given day.b.Find the probability that exactly two of the three plants process more than 5 tons of raw sugar on a given day.c.How much raw sugar should be stocked for the plant each day so that the chance of running out of the raw sugar is only 0.05?

Answer: The mean (μ) of the plants is 4 tons. The probability density function of an exponential distribution is given by:

f(x)=\lambda e^{-\lambda x}\\But\ \lambda= 1/\mu=1/4 = 0.25\\Therefore:\\f(x)=0.25e^{-0.25x}\\

a) P(x > 5) = \int\limits^\infty_5 {f(x)} \, dx =\int\limits^\infty_5 {0.25e^{-0.25x}} \, dx =-e^{-0.25x}|^\infty_5=e^{-1.25}=0.2865

b) Probability that exactly two of the three plants process more than 5 tons of raw sugar on a given day can be solved when considered as a binomial.

That is P(2 of the three plant use more than five tons) = C(3,2) × [P(x > 5)]² × (1-P(x > 5)) = 3(0.2865²)(1-0.2865) = 0.1757

c) Let b be the amount of raw sugar should be stocked for the plant each day.

P(x > a) = \int\limits^\infty_a {f(x)} \, dx =\int\limits^\infty_a {0.25e^{-0.25x}} \, dx =-e^{-0.25x}|^\infty_a=e^{-0.25a}

But P(x > a) = 0.05

Therefore:

e^{-0.25a}=0.05\\ln[e^{-0.25a}]=ln(0.05)\\-0.25a=-2.9957\\a=11.98

a  ≅ 12

6 0
2 years ago
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