Answer:
The expression showing how many more meters Mathieu ran than Edgar ran during that time is
.
Step-by-step explanation:
Edgar ran 'e' meters per second, and Mathieu ran 'm' meters per second. The boys ran for 't' seconds.
The expression
describes how many more meters Mathieu ran than Edgar ran during that time.
We can also use the expression
represent the same quantity.
We know that,

Distance covered by Edgar = te
Distance covered by Mathieu = tm
Difference in distance 
The expression showing how many more meters Mathieu ran than Edgar ran during that time is
.
Given expression :
.
We need to apply power property of logs to rewrite it.
According to log rule of exponents:

If we compare given expression with the rule the exponent part is f, base is 6.
Therefore, we need to bring exponent f in front of log.
Therefore,
.
<h3>And correct option is second option

</h3>
Answer:
$52.50
Step-by-step explanation:
210 divided by 4 equals 52.50
Answer:
a) 0.9644 or 96.44%
b) 0.5429 or 54.29%
Step-by-step explanation:
a) The probability that at least 1 defective card is in the sample P(A) = 1 - probability that no defective card is in the sample P(N)
P(A) = 1 - P(N) .....1
Given;
Total number of cards = 140
Number selected = 20
Total number of defective cards = 20
Total number of non defective cards = 140-20 = 120
P(N) = Number of possible selections of 20 non defective cards ÷ Number of possible selections of 20 cards from all the cards.
P(N) = 120C20/140C20 = 0.0356
From equation 1
P(A) = 1 - 0.0356
P(A) = 0.9644 or 96.44%
b) Using the same method as a) above
P(A) = 1 - P(N) .....1
Given;
Total number of cards = 140
Number selected = 20
Total number of defective cards = 5
Total number of non defective cards = 140-5 = 135
P(N) = 135C20/140C20 = 0.457
From equation 1
P(A) = 1 - 0.4571
P(A) = 0.5429 or 54.29%
Answer:
6 2/3 mL
Step-by-step explanation:
Multiply thru by 100 to get:
1000 + 60x = 30*40 + 30x
30x = 200
x = 6 2/3 mL (amt. of 60% solution needed in the mixture)