We will traduce the sentences into equations.
Let x be the number of hours in the first job, and y be the number of hours in the second job.
Then the equations are:

The above system has many solution, we can select for example:
x = 1, y = 16. So we can work one hour at the first job and 16 hour at the second job.
Answer : Remaining two observation becomes 97 and 107.
Explanation :
Since we have given that
Mean = 100
Modal value = 98
Range = 10
As we know that ,
Range = Highest-Lowest
Let highest observation be x
Let lowest observation be y
So equation becomes x-y=10 ----equation 1
So, observation becomes
x,98,98,y
Now, we use the formula of mean i.e.
Mean = 
So, mean =
So our 2nd equation becomes
x+y=204
On using elimination method of system of linear equation on these two equation we get,
x=97
and

Hence , remaining two observation becomes 97 and 107.
The answer would be ΔKML because the right angle of ΔKML is in the same place as <span>ΔJKL</span>
Answer:
2. 13
Step-by-step explanation:
The least number of classes need for all of the students to be registered in a class is 13 since you want all of the stuednts to be registered so no one should be left out. If we do 12*12 (12 students in each class and there are 12 classes), that would only let 144 students take the swimming classes and 8 students would be left out. We don't want that though since we want all of the students to be registered. So let's go to 12*13 (12 students in each class and there are 13 classes), that would let 156 students take the swimming class. 156>152 so therefore, 13 classes would allow for all 152 students to be registered and it is the least number of classes needed for all the students to be registered in a class (plus you would have 4 seats left for anyone who wants to register in the future but the remainder doesn't matter).