Ask question

Ask question

All categories

Natasha_Volkova [10]

1 year ago

13

Find the length of the leg of a right triangle with leg length b= 21.5 inches and the hypotenuse c= 31.9 inches. Use a calculato

r to estimate the square root to one decimal place.

1 answer:

sweet [91]1 year ago

8 0

Answer:

23.6 (approximate value)

Step-by-step explanation:

a*a+b*b=c*c Pythagorean thereom
(21.5)^2 + b*b = (31.9)^2
b*b= 1017.61 - 462.25
√b*b= √555.36
b=23.6(approximate value)

You might be interested in

Sophie could $330 in a savings account at a simple interest rate of 4% per year. Avi put $290 in a savings account at a simple i

worty [1.4K]

Sophie would’ve earned more
She would’ve earned $37 more

Calculations:
Sophie:
$330(1+4%*2)
=$356
Simple interest: $356-$330
=$26

Avi:
$290(1+5%*2)
=$319
Simply interest: $319-$290
=$29

$29-$26
=$3

8 0

2 years ago

Consider the equation y=2x+5 . Create a table of five ordered pairs that satify the equation. What is the y-intercept of the equ

kupik [55]

Since y=mx+b is the slope-intercept form of a line, where m=slope and b=y-intercept, we can see that:

The y-intercept is 5 (technically the point (0,5))

The x-intercept occurs when y=0 so:

2x+5=0

2x=5

x=2.5

So the x-intercept is the point (2.5, 0)

5 0

1 year ago

Read 2 more answers

The general form of the equation of a circle is 7x2 + 7y2 − 28x + 42y − 35 = 0. The equation of this circle in standard form is

Ede4ka [16]

Answer:

The standard form of a circle is (x-h)^2 + (y-k)^2 = r^2 with (h,k) being the center of the circle and r being the radius. In this case the circle's equation in standard form is (x-2)^2 + (y+3)^2 = 18. Knowing this it's easy to see that the center of the circle (h,k) is (2,-3). Finally the radius is $\sqrt{18}$ or in simplified terms, 3 $\sqrt{2}$

Step-by-step explanation:

7 0

1 year ago

Read 2 more answers

Perform the indicated operation. (y4 - 1) ÷ (y + 1)

Valentin [98]

$The\ domain:\\D:y\neq-1\\\\(y^4-1)\div(y+1)=\dfrac{(y^2)^2-1^2}{y+1}=\dfrac{(y^2-1)(y^2+1)}{y+1}\\\\=\dfrac{(y-1)(y+1)(y^2+1)}{y+1}=(y+1)(y^2+1)=y^3+y^2+y+1\\\\Used:\\(a^n)^m=a^{nm}\\\\a^2-b^2=(a-b)(a+b)$

7 0

2 years ago

Read 2 more answers

Roger and rita each drive at a constant speed between phoenix and san diego. Each driver’s distance for the same section of the

never [62]

Answer:

a)Rita had a 28-mile head start

Step-by-step explanation:

The multiple options have been added in the additional information below the problem statement.

<u>Missing Information:</u>

Since the distance of each driver is not displayed. Let us assume their distances.

Say,

Roger travelled distance = 60 miles

Rita travelled distance = 32 miles

Now as it is given in the problem statement that Roger and Rita both drove at a constant speed between Phoenix and San Diego and they drove "Same Section of the trip" .

Which Means that the distance travelled of both is between Phoenix and San Diego, just their starting points are different but their end point is the same which is San Diego.

<em><u>As we can see RIta had to cover less miles which means she got the head start, now to calculate how much of a head start she got, we need:</u></em>

Head Start Rita got = Distance Roger travelled - Distance Rita Travelled

Head Start Rita got = 60 - 32 = 28 miles

So,

Rita got a Head start of 28 miles which is option (a)

5 0

2 years ago

Read 2 more answers