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Gennadij [26K]
2 years ago
14

In an assessment of the quality of the electrical power​ system, one measure of quality is the degree to which voltage fluctuati

ons cause light flicker in the system. The perception of light flicker x when the system is set at 380kV was measured periodically​ (over 10-minute​ intervals). For transformers supplying heavy industry​ plants, suppose the light flicker distribution was found to follow​ (approximately) a normal distribution with ​% and . If the perception of light flicker exceeds ​%, the transformer is shut down and the system is reset. How likely is it for a transformer supplying a heavy industry plant to be shut down due to light​ flicker?
Mathematics
1 answer:
denis23 [38]2 years ago
6 0

Answer:

The answer is " 0.83"

Step-by-step explanation:

In the question some data is missing, that's value can be defined as follows:

Values:

\ X =  3.3 \\

\mu \ = 2.8 \% \\\sigma = 0.6

Formula:

z= \frac{X - \mu }{\sigma} \\

  = \frac{3.3 - 2.8 }{0.6} \\\\= \frac{ 0.5}{0.6} \\\\= \ 0.83

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2 years ago
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Two boats leave port at noon. Boat 1 sails due east at 12 knots. Boat 2 sails due south at 8 knots. At 2 pm the wind diminishes
Ivan

Answer:

14.86 knots.

Step-by-step explanation:

<em>Given that:</em>

The boats leave the port at noon.

Speed of boat 1 = 12 knots due east

Speed of boat 2 = 8 knots due south

At 2 pm:

Distance traveled by boat 1 = 24 units due east

Distance traveled by boat 2 = 16 units due south

Now, speed of boat 1 changes to 9 knots:

At 3 pm:

Distance traveled by boat 1 = 24 + 9= 33 units due east

Distance traveled by boat 2 = 16+8 = 24 units due south

Now, speed of boat 1 changes to 8+7 = 15 knots

At 5 pm:

Distance traveled by boat 1 = 33 + 2\times 9= 51 units due east

Distance traveled by boat 2 = 24 + 2 \times 15 = 54 units due south

Now, the situation of distance traveled can be seen by the attached right angled \triangle AOB.

O is the port and A is the location of boat 1

B is the location of boat 2.

Using pythagorean theorem:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^{2} = 51^{2} + 54^{2}\\\Rightarrow AB^{2} = 2601+ 2916 = 5517\\\Rightarrow AB = 74.28\ units

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Change in distance per hour = \dfrac{Total\ distance}{Total\ time}

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6 0
1 year ago
According to a human modeling​ project, the distribution of foot lengths of women is approximately Normal with a mean of 23.3 ce
Yakvenalex [24]

Answer:

26.11% of women in the United States will wear a size 6 or​ smaller

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 23.3, \sigma = 1.4

In the United​ States, a​ woman's shoe size of 6 fits feet that are 22.4 centimeters long. What percentage of women in the United States will wear a size 6 or​ smaller?

This is the pvalue of Z when X = 22.4. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{22.4 - 23.3}{1.4}

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8 0
2 years ago
Solve x2 + 6x = 7 by completing the square. Which is the solution set of the equation?
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then, condense the left side of the equation into a squared binomial:

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take the square root of both sides:

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therefore:

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so your solution set is:

x = 1, -7
7 0
1 year ago
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Answer:

23rd term

Step-by-step explanation:

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