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2 years ago

9

Write the denominator of the rational number257/500 in the form 2 m x 5 n , m and n are negative integers Hence write its decima

l expansion without actual division.

1 answer:

maw [93]2 years ago

6 0

Answer:

0.514

Step-by-step Explantion:

Denominator = 500 = 2^2 * 5^3

257/500 = 257/2^2*5^3 = 2*257/2*2^2*5^3 = 514/2^3*5^3 = 514/(2*5)^3 = 514/10^3 = 0.514

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Answer:

17

Step-by-step explanation:

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Shelley is searching online for airline tickets. Two weeks ago, the cost to fly from Boston to Denver was $300. Now the cost i

Nady [450]

Answer:

The percentage increase without baggage fee=25%

The percentage increase with baggage fee=41.66%

Step-by-step explanation:

Given the cost of the airline ticket two weeks ago is $300 and The present airline ticket is $375

We know that when a quantity increases from x to y then The percentage increase is equal to $\frac{y-x}{x} *100$

Here the percentage increase = $\frac{375-300}{300} *100$ =25%

Now the airline charges an extra $50 baggage fee which means teh present value of the airline ticket is $375+$50=$425

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2 years ago

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Pavel [41]

Ok to find the answer all you have to do is multiply 87.60*10=876
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2 years ago

In a health club, research shows that on average, patrons spend an average of 42.5 minutes on the treadmill, with a standard dev

Paha777 [63]

Answer:

0.3114

Option d is right

Step-by-step explanation:

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Given that research shows that on average, patrons spend an average of 42.5 minutes on the treadmill, with a standard deviation of 5.4 minutes

Also given that X is normal

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2 years ago

Consider the graphs of f (x) = StartAbsoluteValue x EndAbsoluteValue + 1 and g (x) = StartFraction 1 Over x cubed EndFraction. T

Westkost [7]

Answer:

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f(x) = IxI + 1

g(x) = 1/x^3.

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How we can prove this?

First, two composite functions are commutative if:

f(g(x)) = g(f(x))

Well, you could use brute force (just replace the values and see if the composite functions are commutative or not)

But i will use a more elegant way.

We can notice two things:

g(x) has a discontinuity at x = 0.

so:

f(g(x)) = I 1/x^3 I + 1

still has a discontinuty at x = 0, but:

g(f(x)) = 1/( IxI + 1)^3

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So now we do not have a discontinuity.

Then the composite functions can not be commutative.

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2 years ago

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