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irga5000 [103]
2 years ago
10

There are 50 students in a class and the professor chooses 15 students at random. what is the probability that you or your frien

d joe are among the chosen students?

Mathematics
2 answers:
Alenkasestr [34]2 years ago
3 0
Try this option (see the attachment). Make design according own requirements.
Note, that the description and details are under green line.

Answer: 0.030921

Sindrei [870]2 years ago
3 0

Answer:

30% probability that Joe is among the chosen students.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the students are chosen is not important, so the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes:

Joe

14 remaining students, from the remaining 49. So

D = C_{49,14} = \frac{49!}{14!(49-14)!} = 675248872536

Total outcomes:

15 students, from a set of 50. So

T = C_{50,15} = \frac{50!}{15!(50-15)!} = 2.2508296 \times 10^{12}

Probability

p = \frac{D}{T} = \frac{675248872536}{2.2508296 \times 10^{12}} = 0.3

30% probability that Joe is among the chosen students.

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Which equation has the solutions x = 5+/- 2 the squire root of 7 over 3
coldgirl [10]
If you look at the quadratic formula:

x=(-b±√(b^2-4ac))/(2a)

We can say that -b=5, b=-5

If I read it right you had ±2√7 which is equal to ±√28, and we know b=-5 so:

±√(25-4ac)=±√28

And since 3=2a, a=1.5 making the above:

±√(25-6c)=±√28

25-6c=28

-6c=3

c=-0.5

So a=1.5, b=-5, and c=-0.5 thus 

y=1.5x^2-5x-0.5

We can check this by reapplying the quadratic formula to the equation above

x=(5±√(25-4(1.5)(-0.5))/3

x=(5±√(25+3))/3

x=(5±√28)/3

x=(5±√(4*7))/3

x=(5±2√7)/3
5 0
2 years ago
981 rounded to nearest 100
sergey [27]

Answer: 1000

Step-by-step explanation:

     9         8       1

Hundred tens one

The question is asking for to round to the nearest hundred (100) which means is rounding to [9] in this question.

The number of the place before the hundreds place is [8] on the tens place.

  • When numbers are greater than or equal to 5, you round up a digit.
  • When numbers are less than 5, you round down a digit.

[8] is greater than 5, so you round 9 up. When rounding 9 up, you get 10.

<h2>So, the final number will be 1000</h2>
6 0
2 years ago
Pat had 9 flowerpots, and she wants to plant a different type of flower in each one. There are 11 types of flowers available at
wariber [46]

<span>In this problem, we will use the combination since the order does not matter but the flower can only be selected once. From the given, we have a total of 11 flower and 9 flowerpots, to get the number of possible combinations, we can write is at 11C9 or 11! / {9! (11-9)!}. The total number of possible combinations is 55</span>

7 0
2 years ago
Read 2 more answers
Point Y is the midpoint of segment XZ. If XY = 2(3x +1) and YZ = 5x + 22, find the value of x.
Ede4ka [16]
<h3>Point Y is the midpoint of segment XZ. Then value of x is 20</h3>

<em><u>Solution:</u></em>

Given that,

<em><u>Point Y is the midpoint of segment XZ</u></em>

XY = 2(3x +1)

YZ = 5x + 22

To find: Value of x

Since, Point Y is the midpoint of segment XZ,

Therefore,

XY = YZ

2(3x + 1) = 5x + 22

6x + 2 = 5x + 22

6x - 5x = 22 - 2

<h3>x = 20</h3>

Thus, value of x is 20

6 0
2 years ago
The instructor had saved $3,500 and rents an apartment for $275 monthly. He believes the point (6, 1850) would be on the equatio
elena-s [515]

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6 0
2 years ago
Read 2 more answers
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