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2 years ago

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There are 50 students in a class and the professor chooses 15 students at random. what is the probability that you or your frien

d joe are among the chosen students?

2 answers:

Alenkasestr [34]2 years ago

3 0

Try this option (see the attachment). Make design according own requirements.
Note, that the description and details are under green line.

Answer: 0.030921

Sindrei [870]2 years ago

3 0

Answer:

30% probability that Joe is among the chosen students.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the students are chosen is not important, so the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Desired outcomes:

Joe

14 remaining students, from the remaining 49. So

$D = C_{49,14} = \frac{49!}{14!(49-14)!} = 675248872536$

Total outcomes:

15 students, from a set of 50. So

$T = C_{50,15} = \frac{50!}{15!(50-15)!} = 2.2508296 \times 10^{12}$

Probability

$p = \frac{D}{T} = \frac{675248872536}{2.2508296 \times 10^{12}} = 0.3$

30% probability that Joe is among the chosen students.

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Which statements about the box plot are correct? Check all that apply.

Rudiy27

Answer:

The correct options are 1 and 3.

Step-by-step explanation:

From the given box plot it is clear that

$\text{Minimum values}=34$

$Q_1=42$

Q₁ is 25% of a data.

$Median=46$

Median is 50% of a data.

$Q_3=70$

Q₃ is 75% of a data.

$\text{Maximum values}=76$

34 is minimum value of the data and 46 is median it means 50% of the data values lies between 34 and 46. Therefore option 1 is correct.

42 is first quartile and and 70 is third quartile. it means 50% of the data values lies between 42 and 70. Therefore option 2 is incorrect.

The difference between Minimum value and first quartile, Maximum value and third quartile is less than 1.5×(IQR), therefore it is unlikely to have any outliers in the data.

Hence option 3 is correct.

The interquartile range of the data is

$IQR=Q_3-Q_1$

$IQR=70-42=28$

The interquartile range is 28. Therefore option 4 is incorrect.

Range of the data is

$Range=Maximum-Minimum$

$Range=76-34=42$

The range is 42. Therefore option 5 is incorrect.

3 0

2 years ago

Read 2 more answers

The number of miles walked, y, varies directly with the number of hours walked, h. After 1.2 hours, Hal had walked 1.8 miles. Fi

Firdavs [7]

Answer:

30 divided by 1.8= 16.6

Step explanation:

7 0

2 years ago

The prices of three t-shirts styles are $24, $30 and $36. the probability of choosing a $24 t-shirt is 1/6. the probability of c

Slav-nsk [51]

$\text{Answer} : \text{The expected value of a t-shirt is \$31.}$

Explanation:

Since we have given that

The prices of three t-shirts styles i.e $24, $30, $36 with their probability is given by

$\frac{1}{6}, \frac{1}{2},\frac{1}{3}$

As we know that,

$E(X)= \sum_{1}^{3}x_iP(x_i)$

$\text{where} x_i \text{ is the prices of t- shirts styles}$

Now,

$x_1= \$24 , x_2=\$30 , x_3=$36$

and

$P(x_1)=\frac{1}{6},P(x_2)=\frac{1}{2}, P(x_3)=\frac{1}{3}$

So,

$E(X)= 24\times \frac{1}{6}+30\times\frac{1}{2}+36\times \frac{1}{3}\\=4+15+12\\=31$

So, the expected value of a t-shirt = $31.

4 0

2 years ago

How many distinct pairs of disjoint non-empty subsets of A are there, the union of which is all of A?

Mrac [35]

A = {1, 2, 5, 6, 8}
{1} U {2, 5, 6, 8}
{2} U {1, 5, 6, 8}
{5} U {1, 2, 6, 8}
{6} U {1, 2, 5, 8}
{8} U {1, 2, 5, 6}
{1, 2} U {5, 6, 8}
{1, 5} U {2, 6, 8}
{1, 6} U {2, 5, 8}
{1, 8} U {2, 5, 6}
{1, 2, 5} U {6, 8}
{1, 2, 6} U {5, 8}
{1, 2, 8} U {5, 6}
{1, 5, 6} U {2, 8}
{1, 5, 8} U {2, 6}
{1, 6, 8} U {2, 5}
The answer is 15 distinct pairs of disjoint non-empty subsets.

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2 years ago

Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional

yaroslaw [1]

Answer:

The statement provided is True.

Step-by-step explanation:

The exponential function representing growth is given as follows:

$y=y_{0}\cdot e^{kt}$

Here,

<em>y</em> = final value

<em>y</em>₀ = initial value

<em>k</em> = growth rate

<em>t</em> = time passed

As the function $e^{x}$ is increasing, then the exponential function representing growth is also increasing.

Thus, the statement provided is True.

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2 years ago