Question

A goblet contains 222 red marbles, 666 green marbles, and 444 blue marbles. If we choose a marble, then another marble without putting the first one back in the goblet, what is the probability that the first marble will be green and the second will be green as well?

Answer 1

Answer : Probability( first will be green and second will be green as well) = 0.024989713

Explanation:

 We have given that,

Number of red marbles = 222

Number of green marbles =666

Number of blue marbles  =444

∴ Total number of marbles =1332

$P( \text{first marble will be green and the second will be green as well})= \frac{666}{1332}\times \frac{665}{1331}$

$=\frac{442890}{1772892}\\=0.024989713$

∴ Probability will be 0.024989713

Answer 2

Answer:

5/22

Step-by-step explanation:

1/2 x 5/11 = 5/22