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frosja888 [35]
2 years ago
13

A goblet contains 222 red marbles, 666 green marbles, and 444 blue marbles. If we choose a marble, then another marble without p

utting the first one back in the goblet, what is the probability that the first marble will be green and the second will be green as well?
Mathematics
2 answers:
Firdavs [7]2 years ago
3 0

Answer : Probability( first will be green and second will be green as well) = 0.024989713

Explanation:

 We have given that,

Number of red marbles = 222

Number of green marbles =666

Number of blue marbles  =444

∴ Total number of marbles =1332

P( \text{first marble will be green and the second will be green as well})= \frac{666}{1332}\times \frac{665}{1331}

=\frac{442890}{1772892}\\=0.024989713

∴ Probability will be 0.024989713

Maksim231197 [3]2 years ago
3 0

Answer:

5/22

Step-by-step explanation:

1/2 x 5/11 = 5/22

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