Answer:
k = - 14
Step-by-step explanation:
given that (x - 5) is a factor of the polynomial then x = 5 is a root and
x³ - x² + kx - 30 = 0 for x = 5, that is
5³ - 5² + 5k - 30 = 0
125 - 25 + 5k - 30 = 0
70 + 5k = 0 ( subtract 70 from both sides )
5k = - 70 ( divide both sides by 5 )
k = - 14
I think you meant it to be not repeating 3 times so
You do 192/3 is 60*3= 180 leaving you with 12 which is 4*3. So 64 is A
Then it’s 300/5 which is 60
455/7. So first see, if I multiply 7 by 60 is it over or under. If it’s over then B is the least and if it is less then C is the least. So 7 *60 is 420
C Being greater, b costs least per night
Answer:
142.2 meters.
Step-by-step explanation:
We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.
Let us find total surface area of box using surface area formula of cuboid.
, where,
= Length of cuboid,
= Breadth of cuboid,
= Width of cuboid.




Therefore, the total surface area of box will be 7584 square cm.
To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.





Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.




Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.
Answer: a) 278382 oz
b) 43 oz
c) 64.1 oz
Step-by-step explanation:
a) 8 T. 1,398 lb. 14 oz. × 6
First we need to change it in 'oz'.
As we know that

so, it becomes,

8 T. 1,398 lb. 14 oz. × 6 becomes

b) 349 lb. 6 oz. ÷ 130
It becomes,

c) 6 T. 294 lb. ÷ 3,071
First it becomes,

At last it becomes,

Hence, a) 278382 oz
b) 43 oz
c) 64.1 oz
Answer:
Step-by-step explanation:
Suppose the time required for an auto shop to do a tune-up is normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - u)/s
Where
x = points scored by students
u = mean time
s = standard deviation
From the information given,
u = 102 minutes
s = 18 minutes
1) We want to find the probability that a tune-up will take more than 2hrs. It is expressed as
P(x > 120 minutes) = 1 - P(x ≤ 120)
For x = 120
z = (120 - 102)/18 = 1
Looking at the normal distribution table, the probability corresponding to the z score is 0.8413
P(x > 120) = 1 - 0.8413 = 0.1587
2) We want to find the probability that a tune-up will take lesser than 66 minutes. It is expressed as
P(x < 66 minutes)
For x = 66
z = (66 - 102)/18 = - 2
Looking at the normal distribution table, the probability corresponding to the z score is 0.02275
P(x < 66 minutes) = 0.02275