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2 years ago

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Irving spent the day shopping and made the following purchases: Item Cost ($) Novel 8.75 Shirt 21.66 Lunch 9.13 Potted plant 16.

89 When Irving was done, he checked his account balance and found he had a total of $95.06. How much money was in Irving’s account to begin with? a. $56.43 b. $151.49 c. $38.63 d. $142.36

2 answers:

laiz [17]2 years ago

7 0

The answer is B. i just took the quiz and got 100%

malfutka [58]2 years ago

5 0

Solution:

Amount spent by Irving:

Item cost($)

Novel 8.75

Shirt 21.66

Lunch 9.13

Potted plant 16.89

Total money spent = $56.43.

Amount of money In Irving account= $95.06.

Amount of money was in Irving’s account to begin with =$56.43+$95.06=$151.49.

Answer:$151.49.

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zzz [600]

Answer:

Step-by-step explanation:

Given that Miguel is playing a game

The box contains 4 chips, 2 with number 1, and other two differntly numbered as 3 and 5.

OUt of these 4, 2 chips are drawn

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Prob (drawing differnt numbers) = 1-1/6 = $\frac{5}{6}$

Hence prob of winning 2 dollars = $\frac{1}{6}$

Prob of losing 1 dollar = $\frac{5}{6}$

b) Expected value = sum of prob x amount won

= $\frac{1}{6}2+\frac{5}{6}(-1)=-\frac{1}{2}$

c) Miguel can expect to lose 1/2 dollars for every game he plays

d) If it is to be a fair game expected value =0

i.e. let the amount assigned be s

Then $\frac{1}{6}s-\frac{5}{6}=0\\s=5$

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2 years ago

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A map of Colorado says that the scale is 1 inch to 20 miles or 1 to 1,267,200. Are these two ways of reporting the scale the sam

goldenfox [79]

Answer:

1,267,200

Step-by-step explanation:

Given that the map reported that the scale is 1 inch to 20 miles.

Recall that there are 63,360 inches in 1 mile, thus, in 20 miles, we have 20 x 63,360 = 1,267,200

Therefore, the scale of 1 inch to 20 miles can also be represented as 1 to 1,267,200

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2 years ago

Determine the area (in units2) of the region between the two curves by integrating over the x-axis. y = x2 − 24 and y = 1

astra-53 [7]

Answer:

The area of the region between the two curves by integration over the x-axis is 9.9 square units.

Step-by-step explanation:

This case represents a definite integral, in which lower and upper limits are needed, which corresponds to the points where both intersect each other. That is:

$x^{2} - 24 = 1$

Given that resulting expression is a second order polynomial of the form $x^{2} - a^{2}$ , there are two real and distinct solutions. Roots of the expression are:

$x_{1} = -5$ and $x_{2} = 5$ .

Now, it is also required to determine which part of the interval $(x_{1}, x_{2})$ is equal to a number greater than zero (positive). That is:

$x^{2} - 24 > 0$

$x^{2} > 24$

$x < -4.899$ and $x > 4.899$ .

Therefore, exists two sub-intervals: $[-5, -4.899]$ and $\left[4.899,5\right]$ . Besides, $x^{2} - 24 > y = 1$ in each sub-interval. The definite integral of the region between the two curves over the x-axis is:

$A = \int\limits^{-4.899}_{-5} [{1 - (x^{2}-24)]} \, dx + \int\limits^{4.899}_{-4.899} \, dx + \int\limits^{5}_{4.899} [{1 - (x^{2}-24)]} \, dx$

$A = \int\limits^{-4.899}_{-5} {25-x^{2}} \, dx + \int\limits^{4.899}_{-4.899} \, dx + \int\limits^{5}_{4.899} {25-x^{2}} \, dx$

$A = 25\cdot x \right \left|\limits_{-5}^{-4.899} -\frac{1}{3}\cdot x^{3}\left|\limits_{-5}^{-4.899} + x\left|\limits_{-4.899}^{4.899} + 25\cdot x \right \left|\limits_{4.899}^{5} -\frac{1}{3}\cdot x^{3}\left|\limits_{4.899}^{5}$

$A = 2.525 -2.474+9.798 + 2.525 - 2.474$

$A = 9.9\,units^{2}$

The area of the region between the two curves by integration over the x-axis is 9.9 square units.

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masha68 [24]

Answer: y = 3x + 60

<u>Step-by-step explanation:</u>

Set up two equations and solve the system:

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- <u>(150 = 30x + b)</u>

120 = 40x

3 = x

Input "x" into one of the equations and solve for "b":

150 = 30x + b

150 = 30(3) + b

150 = 90 + b

60 = b

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This means that there is a flat fee of $60 plus a rate of $3 per student

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Answer:

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Integers are; H and D

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Please find attached the location of the letters on the real number system

Step-by-step explanation:

Rational numbers are numbers that can be expressed as the ratio, a/b, of two numbers as a/b where a and b are integers

Integers are the negative and positive whole numbers

Whole numbers are the positive counting numbers from 0 and above

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2 years ago