The general vertex form of the a quadratic function is y = (x - h)^2 + k.
In this form, the vertex is (h,k) and the axis of symmetry is x = h.
Then, you only need to compare the vertex form of g(x) with the general vertex form of the parabole to conclude the vertex point and the axis of symmetry.
g(x) = 5(x-1)^2 - 5 => h = 1 and k = - 5 => theis vertex = (1, -5), and the axis of symmetry is the straight line x = 1.
<span>Answer: the vertex is (1,-5) and the symmetry axis is x = 1.</span>
Answer:
Step-by-step explanation:
: Read and write decimals to thousandths using base-ten numerals, number names, and expanded form, e.g., 347.392 = 3 × 100 + 4 × 10 + 7 × 1 + 3 × (1/10) + 9 × (1/100) + 2 × (1/1000).
To solve this problem you must apply the proccedure shown below:
1. You have that the hyperbola <span>has a vertex at (0,36) and a focus at (0,39).
2. Therefore, the equation of the directrices is:
a=36
a^2=1296
c=39
y=a^2/c
3. When you susbtitute the values of a^2 and c into </span>y=a^2/c, you obtain:
<span>
</span>y=a^2/c
<span> y=1296/13
4. When you simplify:
y=432/13
Therefore, the answer is: </span><span>y = ±432/13</span>
