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Salsk061 [2.6K]
2 years ago
5

A catering company charges $300 plus $40 per guest for a wedding. Sarah and Eric do not want to spend more than $5,000 on cateri

ng. Write and solve an inequality in terms of the number of guests, g, that can be invited. A) 300 - 40g ≥ 5000; g ≥ 117 B) 300 - 40g ≤ 5000; g ≤ 118 C) 300 + 40g ≤ 5000; g ≤ 117 D) 300 + 40g ≤ 5000; g ≤ 118
Mathematics
2 answers:
Fynjy0 [20]2 years ago
8 0
Your answer would be either c or d
marta [7]2 years ago
5 0
<span> 300 + 40g ≤ 5000; g ≤ 118</span>
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1.) You are one of five people who have been hired to mow the lawn at the local college. Each week, the dimensions of the plot y
iren [92.7K]

Answer:

1a)  Length = 7x + 3  & Width = 4x - 2

1b)  Area = 28x^2 -2x -6

1c)  Area = 2774 sq. m

2.  (x-4)(y+7)

Step-by-step explanation:

1a)

The length given as words is "3 more than 7 times x"

The width given as words is "4 times x minus 2"

The expression for length would be  7x + 3

The expression for width would be 4x - 2

1b)

The area is length * width

Since we already know the algebraic expressions for length and width from part (a) above, we use the formula:

Area = (7x+3)(4x-2) = 28x^2 -14x + 12x - 6 = 28x^2 -2x -6

Area = 28x^2 -2x -6

1c)

Given x = 10, we put this into the area expression we found in (b) above.Let's see:

28x^2 -2x -6\\=28(10)^2 -2(10) -6\\=2774

Area = 2774 sq. m

2.

We can group the first two terms and next two terms and write up:

xy-4y+7x-28\\(xy-4y)+(7x-28)\\y(x-4)+7(x-4)\\(x-4)(y+7)

That's the factored form.

8 0
2 years ago
Read 2 more answers
Three times the sum of half Carlita’s age and 3 is at least 12.What values represent Carlita’s possible age? graph the solution
gulaghasi [49]

<em><u>3 x 12 </u></em>

<em><u>I think because you find out how to graph in the corresponding area on the graph </u></em>

5 0
2 years ago
Read 2 more answers
A 92.0 kg football player at 6.50 m/s North collides with an 85.0 kg football player running at 6.00 m/s south. The 92.0 kg foot
s2008m [1.1K]

Answer:

-1.13 m/s

Step-by-step explanation:

Parameters given:

Mass of first footballer, M = 92 kg

Initial velocity of first footballer, U = 6.5 m/s (taking North to be the +ve y axis)

Mass of second footballer, m = 85 kg

Initial velocity of second footballer, u = -6.0 m/s (taking South to be the -ve y axis)

Final velocity of first footballer, V = 2.0 m/s

We need to find the final velocity of the second football (v)

Applying the principle of conservation of momentum, we have that, in a system:

Total Initial Momentum = Total Final Momentum

(M * U) + (m * u) = (M * V) + (m * v)

(92 * 6.5) + (85 * -6) = (92 * 2) + (85 * v)

598 - 510 = 184 + 85v

88 = 184 + 85v

88 - 184 = 85v

-96 = 85v

=> v = -96 / 85

v = -1.13 m/s

The final velocity of the 85 kg player is -1.13 m/s i.e 1.13 m/s South

5 0
2 years ago
Gary used landscape timbers to create a border around a garden shaped like a right triangle. The longest two timbers he used are
Cloud [144]

Answer:

9 feet

Step-by-step explanation:

Given:

The border of the garden is a right angled triangle.

Two lengths are given as 12 ft and 15 ft.

Let the length of the shortest timber be 'x' feet.

Now, in a right angled triangle, the longest length is called the hypotenuse.

As 15 feet is the largest length, it is the hypotenuse of the triangle. Now, applying Pythagoras theorem, we get:

(Leg1)^2+(Leg2)^2=(Hypotenuse)^2\\x^2+12^2=15^2\\x^2+144=225\\x^2=225-144\\x^2=81\\x=\pm \sqrt{81}=\pm 9

The negative value is neglected as length can never be negative.

Therefore, the length of the shortest timber is 9 feet.

8 0
2 years ago
Nick has to build a brick wall. Each row of the wall requires 62 bricks. There are 10 rows in the wall. How many bricks will Nic
Delicious77 [7]
10 x 62 is the equation for this problem because every row has 62 and there are 10 rows.
7 0
2 years ago
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