To answer this kinda question, we gotta tackle it year by year.
By the end of the first year, the tree would grow by 2% = 102% of its original height.
Year 1: 102% x 50 = 51 feet
Year 2: 103% x 51 = 52.02 feet
Hope I helped!! xx
Answer:
Remember that:
Speed = distance/time.
Then we can calculate the average speed in any segment,
Let's make a model where the average speed at t = t0 can be calculated as:
AS(t0) = (y(b) - y(a))/(b - a)
Where b is the next value of t0, and a is the previous value of t0. This is because t0 is the middle point in this segment.
Then:
if t0 = 100s
AS(100s) = (400ft - 0ft)/(200s - 0s) = 2ft/s
if t0 = 200s
AS(200s) = (1360ft - 50ft)/(300s - 100s) = 6.55 ft/s
if t0 = 300s
AS(300s) = (3200ft - 400ft)/(400s - 200s) = 14ft/s
if t0 = 400s
AS(400s) = (6250s - 1360s)/(500s - 300s) = 24.45 ft/s
So for the given options, t = 400s is the one where the velocity seems to be the biggest.
And this has a lot of sense, because while the distance between the values of time is constant (is always 100 seconds) we can see that the difference between consecutive values of y(t) is increasing.
Then we can conclude that the rocket is accelerating upwards, then as larger is the value of t, bigger will be the average velocity at that point.
Given:
Total number of girls in her class = 16
Total number of boys in her class = 14
To find:
The number of different ways of choosing one girl and one boy.
Solution:
We have,
Total number of girls = 16
Total number of boys = 14
So,
Total number of ways to select one girl from 16 girls = 16
Total number of ways to select one boy from 14 boys = 14
Now, number of different ways of choosing one girl and one boy is

Therefore, the required number of different ways is 224.
Answer:

Step-by-step explanation:
<em>Subtract the students who don't have protractors from the students who have mathematical instruments.</em>
