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2 years ago

6

The smith family bought a new tent for a camping trip with a base of 9 by 15 and a height of 7. What is the volume of their new

tent?

1 answer:

dedylja [7]2 years ago

4 0

472.5 it's a pryamind or triangular pyramid. so 9x15x7/2

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Find the amount of time.<br> I=$450, P=$2400, r=7.5%<br> Help!

faust18 [17]

I = PRT.....rearrange = I / PR = T
I = 450
R = 7.5%...turn to decimal = 0.075
P = 2400

I / (PR) = T
450 / (2400 * 0.075) = T
450 / 180 = T
2.5 = T...so time is 2.5 years, or 2 1/2 years

8 0

2 years ago

Suppose that the weight of seedless watermelons is normally distributed with mean 6.1 kg. and standard deviation 1.9 kg. Let X b

horrorfan [7]

Answer:

a. $X\sim N(\mu = 6.1, \sigma = 1.9)$ b. 6.1 c. 0.6842 d. 0.4166 e. 0.1194 f. 8.5349

Step-by-step explanation:

a. The distribution of X is normal with mean 6.1 kg. and standard deviation 1.9 kg. this because X is the weight of a randomly selected seedless watermelon and we know that the set of weights of seedless watermelons is normally distributed.

b. Because for the normal distribution the mean and the median are the same, we have that the median seedless watermelong weight is 6.1 kg.

c. The z-score for a seedless watermelon weighing 7.4 kg is (7.4-6.1)/1.9 = 0.6842

d. The z-score for 6.5 kg is (6.5-6.1)/1.9 = 0.2105, and the probability we are seeking is P(Z > 0.2105) = 0.4166

e. The z-score related to 6.4 kg is $z_{1} = (6.4-6.1)/1.9 = 0.1579$ and the z-score related to 7 kg is $z_{2} = (7-6.1)/1.9 = 0.4737$ , we are seeking P(0.1579 < Z < 0.4737) = P(Z < 0.4737) - P(Z < 0.1579) = 0.6821 - 0.5627 = 0.1194

f. The 90th percentile for the standard normal distribution is 1.2815, therefore, the 90th percentile for the given distribution is 6.1 + (1.2815)(1.9) = 8.5349

7 0

2 years ago

a bird leaves its nest and travels 20 miles per hour downwind for xx hours. on the return trip, the bird travels 4 miles per hou

Rudik [331]

A. if the return trip is the same then the bird traveled 40miles
b. the time of the trip is x hours + 6/x-4

3 0

2 years ago

Read 2 more answers

What is the product? StartFraction x squared minus 16 Over 2 x + 8 EndFraction times StartFraction x cubed minus 2 x squared + x

zubka84 [21]

Answer:

[x(x - 1)(x - 4)]/(2(x + 4))

Step-by-step explanation:

We want to find;

[(x² - 16)/(2x + 8)] * [(x³ - 2x² + x)/(x² + 3x - 4)]

Now,

x² - 16 can be factorized as;

(x + 4)(x - 4)

Also, 2x + 8 can be factorized as;

2(x + 4)

Also, (x³ - 2x² + x) can factorized as;

x[x² - 2x + 1] = x[(x - 1)(x - 1)]

Also,(x² + 3x - 4) can be factorized out as; (x - 1)(x + 4)

So plugging in these factorized forms into the equation in the question, we have;

[(x + 4)(x - 4)/(2(x + 4))] * [x[(x - 1)(x - 1)] /((x - 1)(x + 4))

This gives;

((x - 4)/2) * x(x - 1)/(x +4)

This gives;

[x(x - 1)(x - 4)]/(2(x + 4))

8 0

2 years ago

Read 2 more answers

A relationship between x and y is defined by the equation y=3x +1/2 which statements are true of this relationship? Select all t

bezimeni [28]

Answer:

a.

b.

d.

Step-by-step explanation:

4 0

1 year ago