This is called the pythagorean theorem: a^2 + b^2 = c^2.
Basically, the sum of one side squared + the side of another side squared = the length of the longest side (or hypotenuse).
We have to do the following math:
4 * 4 = 16
6 * 6 = 36
16 + 36 = 52.
We know that 52 = c^2
So we have to
to get 7.21
You do not agree with Ted.
Answer:
A. True
Step-by-step explanation:
The Triangle Inequality Theorem says that the sum of any two sides must be greater than the third side. Let's see if this is true.
a + b
9 + 1 = 10>9
a + c
9 + 9 = 18>1
c + b
9 + 1 = 10>9
9^ ? 3^2 + 7^2
81 ? 9 + 49
81 > 58
c^ > a^2 + b^2
answer is obtuse triangle
The answer is 1840 because you have to do 10x8 then multiply that by 23 and get 1840
Answer:
y2 = C1xe^(4x)
Step-by-step explanation:
Given that y1 = e^(4x) is a solution to the differential equation
y'' - 8y' + 16y = 0
We want to find the second solution y2 of the equation using the method of reduction of order.
Let
y2 = uy1
Because y2 is a solution to the differential equation, it satisfies
y2'' - 8y2' + 16y2 = 0
y2 = ue^(4x)
y2' = u'e^(4x) + 4ue^(4x)
y2'' = u''e^(4x) + 4u'e^(4x) + 4u'e^(4x) + 16ue^(4x)
= u''e^(4x) + 8u'e^(4x) + 16ue^(4x)
Using these,
y2'' - 8y2' + 16y2 =
[u''e^(4x) + 8u'e^(4x) + 16ue^(4x)] - 8[u'e^(4x) + 4ue^(4x)] + 16ue^(4x) = 0
u''e^(4x) = 0
Let w = u', then w' = u''
w'e^(4x) = 0
w' = 0
Integrating this, we have
w = C1
But w = u'
u' = C1
Integrating again, we have
u = C1x
But y2 = ue^(4x)
y2 = C1xe^(4x)
And this is the second solution
