Answer: IX - 4I ≤ 4
Step-by-step explanation:
In the numer line we can see that our possible values of x are in the range:
0 ≤ x ≤ 8
And we want to find an absolute value equation such that this set is the set of possible solutions.
An example can be:
IX - 4I ≤ 4
To construct this, we first find the midpoint M of our set, in this case is 4.
Then we write:
Ix - MI ≤ IMI
Notice that i am using the minor and equal sign, this is because the black dots means that the values x = 0 and x = 8 are included, if the dots were empty dots, it would be an open set and we should use the < > signs.
Answer:
The larger cross section is 24 meters away from the apex.
Step-by-step explanation:
The cross section of a right hexagonal pyramid is a hexagon; therefore, let us first get some things clear about a hexagon.
The length of the side of the hexagon is equal to the radius of the circle that inscribes it.
The area is

Where
is the radius of the inscribing circle (or the length of side of the hexagon).
Now we are given the areas of the two cross sections of the right hexagonal pyramid:
From these areas we find the radius of the hexagons:
Now when we look at the right hexagonal pyramid from the sides ( as shown in the figure attached ), we see that
form similar triangles with length
Therefore we have:

We put in the numerical values of
,
and solve for
:

Answer:
13, 16, 18
Step-by-step explanation:
Sabemos que podemos calcular el total de plumas amarillos, por medio de la media.
16 = (12 + 14 + 15 + 24 + x + y + z) / 7
16 * 7 = 12 + 14 + 15 + 24 + x + y + z
112 = 65 + x + y + z
x + y + z = 112-65
x + y + z = 47
sabemos que la mediana es el valor medio, y que ese 46 debe dividirse entre 3 valores porque son 3 cajas, entonces debemos buscar los números adecuados para el valor 15 esté en la mitad, es decir de cuarto.
Sin meter los valores nuevos, el ranking sería así:
12
14
15
24
el 15 esta de tercero, para que quede de cuarto, debe tener dos valores por debajo y un por arriba, así:
X
12
14
15
y
z
24
Por lo tanto, valores mayores a 15 serían por ejemplo y = 16 y z = 18:
16 + 18 = 34
x = 47-34 = 13
quedaría:
12
13
14
15
dieciséis
18 años
24
Si recalculamos la media:
m = (12 + 14 + 15 + 24 + 13 + 16 + 18) / 7 = 16
Work the information to set inequalities that represent each condition or restriction.
2) Name the
variables.
c: number of color copies
b: number of black-and-white copies
3)
Model each restriction:
i) <span>It
takes 3 minutes to print a color copy and 1 minute to print a
black-and-white copy.
</span><span>
</span><span>
3c + b</span><span>
</span><span>
</span><span>ii) He needs to print
at least 6 copies ⇒
c + b ≥ 6</span><span>
</span><span>
</span><span>iv) And must have
the copies completed in
no more than 12 minutes ⇒</span>
3c + b ≤ 12<span />
4) Additional restrictions are
c ≥ 0, and
b ≥ 0 (i.e.
only positive values for the number of each kind of copies are acceptable)
5) This is how you
graph that:
i) 3c + b ≤ 12: draw the line 3c + b = 12 and shade the region up and to the right of the line.
ii) c + b ≥ 6: draw the line c + b = 6 and shade the region down and to the left of the line.
iii) since c ≥ 0 and b ≥ 0, the region is in the
first quadrant.
iv) The final region is the
intersection of the above mentioned shaded regions.v) You can see such graph in the attached figure.