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Ira Lisetskai [31]
2 years ago
15

Alexis invests $475 in a bank account that earns 1.25% interest compounded annually. Which function models the growth of her inv

estment over x years?
Mathematics
1 answer:
olchik [2.2K]2 years ago
8 0
Answer: The function that modes this situation would be: y = 475(1 + .0125)^x.

This is an example of an exponential equation. These equations are always in the form y = ab^x.

The a value is the starting value. The b value is the interest rate. The x value is the number of years.

The only thing to be careful about is the rate. We are adding 1.25% or 0.125. Make sure that you are adding 1 whole to the 1.25% and don't just use 0.125.
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Answer: 2,000

Step-by-step explanation: 22,000 - 20,000 = 2,000

Angie’s current equity on her car is 2,000

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In ΔVWX, the measure of ∠X=90°, the measure of ∠W=9°, and WX = 8.7 feet. Find the length of XV to the nearest tenth of a foot.
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Step-by-step explanation:

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What numbers are less than 2.98
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Answer:

... anything less than 2.98??

Step-by-step explanation:

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1 year ago
The class is selling food at the school fair. Pretzels cost $1.50, and bottles of water cost $1.00. The class sold a total of 10
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The number of people that enter a drugstore in a given hour is a Poisson random variable with parameter λ = 10. Compute the cond
Nonamiya [84]

Answer:

The probability is 0.2650

Step-by-step explanation:

Let's start assuming that men and women come in at the same rate.

Let's define the following random variables :

X : ''Number of people that enter a drugstore''

M : ''Number of men that enter a drugstore''

W : ''Number of women that enter a drugstore''

The number of people will be the number of men plus the number of women

⇒

X = M + W

We are also assuming that M and W are independent random variables.

X ~ Po (10)

M ~ Po (λ1)

W ~ Po (λ2)

λ1 = λ2 because we assumed that men and women come in at the same rate.

λ1 = λ2 = λ

λ1 + λ2 = λ + λ ⇒ 2λ = 10 ⇒ λ = 5

M ~ Po (5)

W ~ Po (5)

Because X is the sum of two independent Poisson random variables.

We are looking for :

P(M\leq 3/W=10)=P(M\leq 3)

Because we assume independence.

P(M\leq 3)= P(M=0)+P(M=1)+P(M=2)+P(M=3)

P(M=m)=\frac{5^{m}}{m!}e^{-5} because is a Poisson random variable with λ = 5

P(M\leq 3)=\frac{5^{0}}{0!}e^{-5}+\frac{5^{1}}{1!}e^{-5}+\frac{5^{2}}{2!}e^{-5}}+\frac{5^{3}}{3!}e^{-5}

P(M\leq 3)=e^{-5}+5e^{-5} +(\frac{25}{2})e^{-5} +\frac{125}{6}e^{-5}=0.2650

P(M\leq 3)=0.2650

5 0
2 years ago
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