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schepotkina [342]
1 year ago
6

This week, Michael collected $468 for delivering newspapers. He had 40 repeat customers and 18 new ones. As an incentive, he cha

rged the new subscribers $3 less than the repeat customers. If x represents the amount Michael collects from each repeat customer, which equation models this problem?
Mathematics
2 answers:
lys-0071 [83]1 year ago
8 0

Answer:

Equation will be 40x + 18(x - 3) = 468

Step-by-step explanation:

If 'x' represents the amount Michael collects from each repeat customers then amount collected from 40 customers = 40x

If he charged $3 less than the repeat customers then amount charged from 18 customers = $18(x - 3)

Total amount he collected = $468

Therefore, the equation modeling the situation will be

Amount collected from repeated customers + Amount collected from new customers = Total amount collected

40x + 18(x - 3) = 468

loris [4]1 year ago
7 0
468=40x+18(x-3)
468=40x+18x-54
468=58x-54
522=58x
9=x
I'm not sure if you need to know x at all, if not, the top equation is all you need.
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The GPA of accounting students in a university is known to be normally distributed. A random sample of 20 accounting students re
Vladimir79 [104]

Answer:

The 95% of confidence intervals

(2.84 ,2.99)

Step-by-step explanation:

A random sample of 20 accounting students results in a mean of 2.92 and a standard deviation of 0.16

given small sample size n =20

sample mean x⁻ =2.92

sample standard deviation 'S' =0.16

level of significance ∝ =  0.95

The 95% of confidence intervals

x^{-}  ± t_{\alpha } \frac{S}{\sqrt{n} }

the degrees of freedom γ=n-1 =20-1=19

t-table 2.093

(x^{-}  - t_{\alpha } \frac{S}{\sqrt{n} },x^{-}  + t_{\alpha } \frac{S}{\sqrt{n} })

(2.92 - 2.093(\frac{0.16}{\sqrt{20} } ,2.92+2.093(\frac{0.16}{\sqrt{20} } )

(2.92-0.0748,2.92+0.0748)

(2.84 ,2.99)

Therefore the 95% of confidence intervals

(2.84 ,2.99)

4 0
1 year ago
Tim Tradesman estimates his taxable income will be $7,500. He is paid every two weeks or 26 times a year.
alisha [4.7K]
Given:
Taxable income: 7,500
Paid every two weeks or 26 weeks in a year

Based on 2007 Federal Income Tax Table for Single Taxpayer, Tim is under the tax range over $0 but not over $7,825. The tax is 10% of the amount over $0.

<span>1. Finds the tax rate for his income level =10 %

2. Enters the base amount = $7,500

3. Enters the amount of tax owed = $7,500 * 10% = $750

4. Divides by 26 = $750 / 26 = $28.85 tax withheld from biweekly wages.</span>
8 0
1 year ago
Read 2 more answers
The average lifetime of a certain new cell phone is 3.4 years. The manufacturer will replace any cell phone failing within three
melisa1 [442]

Answer:

68% of these phones last 3.87 years.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

The average lifetime of a certain new cell phone is 3.4 years.

This means that m = 3.4, \mu = \frac{1}{3.4} = 0.2941

So

P(X \leq x) = 1 - e^{-0.2941x}

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This is x for which:

P(X \leq x) = 0.68

P(X \leq x) = 1 - e^{-0.2941x}

Then

0.68 = 1 - e^{-0.2941x}

e{-0.2941x} = 0.32

\ln{e{-0.2941x}} = \ln{0.32}

-0.2941x = \ln{0.32}

x = -\frac{\ln{0.32}}{0.2941}

x = 3.87

68% of these phones last 3.87 years.

4 0
1 year ago
the number of tickets sold at the Amazing Art Museum on Saturday was 175% of the ticket sales on Friday. If 2,000 tickets were s
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2000*1.75 makes 3500 tickets sold Saturday.
4 0
2 years ago
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Add all flowers to get denominator

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7/11 chance
3 0
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