Hello there,

There is a total of 40 animals in that in 10 zebras, 10 lions, 10 elephants, and 10 monkeys.
So the probability of them both being lions is pretty rare. 2/40 so that would give you a 1/20 chance of both crackers being both lions.

I hope this helps!

7 0

2 years ago

Find the first, fourth, and eighth terms of the sequence. A(n) = –3 • 2^n–1

Sphinxa [80]

A(n) = –3 • 2⁽ⁿ⁻¹⁾

for n = 1 , A₁ = -3.(2)⁰ = -3
for n = 2 , A₂ = -3.(2)¹ = -6
for n = 3 , A₃ = -3.(2)² = -12
for n = 4 , A₄ = -3.(2)³ = -24
...........................................
for n = 8 , A₈ = -3.(2)⁷ = -384

4 0

1 year ago

M∠1=45° and m∠3=65°

7nadin3 [17]

Answer:

In Right Δ ABC with right angle B,

∠A=(3 x -8)°, ∠B=90°, ∠C=(x-2)°

∠A+∠B+∠C=180°[∠ sum property of triangle]

3 x-8+90 + x-2=180

Adding and subtracting like terms

4 x-10+90=180

4 x+80=180

4 x=180-80

4 x=100

x=100/4

x=25°

∠A=3×25-8=75-8=67°

6 0

1 year ago

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The weight, w, of a spring in pounds is given by 0.9 times the square root of the energy, E, stored by the spring in joules. If

frutty [35]

For this case we have the following equation:
$w = 0.9* \sqrt{E}$
Where,
w: The weight of a spring in pounds
E: the energy stored by the spring in joules.
Substituting values we have:
$w = 0.9* \sqrt{12}$
Making the corresponding calculation:
$w=3.12$
Answer:
the approximate weight of the spring in pounds is:
$w=3.12$

4 0

1 year ago

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