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2 years ago

A hyperbola centered at the origin has a vertex at (0, 36) and a focus at (0, 39)

2 answers:

4 0

To solve this problem you must apply the proccedure shown below:

1. The vertex i at (0, 36) and a focus at (0, 39), then you have:

a=36
a^2=1296

2. The directrix is:

y=a^2=c
c=39
y=1296/39
y=432/13

Therefore, the answer is the option D, which is: D. y=± 432/13

solniwko [45]2 years ago

4 0

Answer:

D. y=± 432/13

Step-by-step explanation:

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Evaluate 8a-1+0.5b8a−1+0.5b8, a, minus, 1, plus, 0, point, 5, b when a=\dfrac14a=

professor190 [17]

Answer: $6$

Step-by-step explanation:

Given the following expression:

$8a-1+0.5b$

You need to substitute the given values of "a" and "b" into the expression. Notice that these values are:

$a=\frac{1}{4}\\\\b=10$

Then;

$8a-1+0.5b=8(\frac{1}{4})-1+0.5(10)$

Now you must solve the multiplications:

$=\frac{8}{4}-1+5=2-1+5$

The final step is to add the numbers. Therefore, you get the following answer:

$=6$

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Step-by-step explanation:

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Answer: The required inequality is $x+\dfrac{1}{4}x+\dfrac{3}{2}x>22.$ and its solution is $x>8.$

Step-by-step explanation: Given that Mustafa, Heloise, and Gia have written more than a combined total of 22 articles for the school newspaper.

Also, Heloise has written $\frac{1}{4}$ as many articles as Mustafa has and Gia has written $\frac{3}{2}$ as many articles as Mustafa has.

We are to write an inequality to determine the number of articles, m, Mustafa could have written for the school newspaper. Also, to solve the inequality.

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$x+\dfrac{1}{4}x+\dfrac{3}{2}x>22.$

And the solution of the above inequality is as follows :

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